allelic or not, what if two morphs just sit on the same chromosome pair? But otherwise they dont affect each other, nothing really visible, its just that you hit a wall when you try to combine them, because you can only have two of these genes maximum. One gene per chromosome, chromosomes are in the same pair, so a snake can only have two of these, one from mom one from dad... you get the idea. If two true recessives would have that issue, and you try to combine them, the first thing you notice is that when breeding double hets to double hets, the odd gods just seem to hate you very very much and you just fail to hit the double recessive visual.
the complete genome of the ball python only has 18 chromosomes. and how many base morphs do we have?
we know 6 gene complexes so far. i just for fun tried to find morphs that prove that all these complexes are, in fact, seperate. Basically going at the problem backwards: no assumptions, i just see how far i can go simply by proving that two genes are NOT on the same chromosome and fully compatible.
a sample of my findings so far, just for the known gene complexes, and yes i use my own abbreviations and terms:
Code:
known 6 complexes set:
BEL, albino, pied, Cin/BlkPa/RedAx, Ivory/Superstripe, Disco/F/Sulfur/V
BEL albino: albino lesser, albino mojave, albino super mojave , ? <<<<done
BEL pied: lesser pied, enchi lesser pied, mystic pied, mojave pied <<<<<done
BEL Cin/BlkPa/RedAx: super cin mojave, lesser super cin, lesser red ax, red ax mystic <<<<<done
BEL Ivory/Superstripe: ivory mojo phantom, butter superstripe, phantom SS, mojo SS, ...<<<<<done
BEL Disco/F/Sulfur/V: sulfur mystic mojave, sulfur super mojave, super mojave vanilla <<<<done
albino pied: clear visible albino pied <<<<<done
albino Cin/BlkPa/RedAx: albino super cinny, albino super black pastel <<<<<done
albino Ivory/Superstripe: albino (+pastel) yellow belly, albino ivory <<not much
albino Disco/F/Sulfur/V: !!!!!!! !!!completely missing!!!
pied Cin/BlkPa/RedAx: super cinnamon pied, lots of cinnamon pied, super blkpa pied. <<<<<done
pied Ivory/Superstripe: pumpkin pied, ivory pied, <<not much
pied Disco/F/Sulfur/V: fire pied < just 1 morph
Cin/BlkPa/RedAx Ivory/Superstripe: cinnamon superstripe, black pastel superstripe <<not much
Cin/BlkPa/RedAx Disco/F/Sulfur/V: mercury ball (fire supercinny), ..? < just 1 morph
Ivory/Superstripe Disco/F/Sulfur/V: fire ivory, ivory vanilla, fire pastel superstripe,
lots of vanilla superstripe <<<<<done
so, im almost done proving that the 6 known BP gene complexes do sit on different chromosome pairs by compiling morphs that contain 3 or 4 copies of just the right genes. i have already proven that the 6 known gene complexes sit on at least 5 different chromosomes. (ive also already proven that clown does not sit on any of the chromosomes inhabited by the 6 known gene complexes, i found all morphs required to do so. with enchi i ran into an issue.)
you know that feeling when you are 90% done with something, and then hit a wall. about visible or not.... just an albino fire, should be visible, at least if you have a clutch containing albino and albino fire. i mean, someone bred an albino pied blue eye lucy and proved it out, people go to crazy lengths for a world first, or so you would think. low-hanging fruit for a world first morph i think.
or, the enchi issue.... enchi red axanthic, super enchi cinnamon, super enchi het red axanthic, super enchi black pastel, enchi cinnamon het red axanthic, enchi black pastel het red axanthic. <----- From what we know, only super cinnamon, super black pastel, and cinnamon black pastel destroy the pattern and lead to patternless snakes. All the other enchi combos i listed could, as far as we know, have a pattern, at least they dont contain something that would definitively ruin the pattern. All of these would be world firsts that noone seems to have done yet, all are either a super + one more gene, or a 3-gene combo.