Vote for BP.Net for the 2013 Forum of the Year! Click here for more info.

» Site Navigation

» Home
 > FAQ

» Online Users: 753

1 members and 752 guests
Most users ever online was 47,180, 07-16-2025 at 05:30 PM.

» Today's Birthdays

None

» Stats

Members: 75,905
Threads: 249,107
Posts: 2,572,121
Top Poster: JLC (31,651)
Welcome to our newest member, Pattyhud
Results 1 to 10 of 20

Threaded View

  1. #16
    BPnet Veteran
    Join Date
    08-31-2011
    Posts
    649
    Thanks
    193
    Thanked 428 Times in 263 Posts
    Images: 21

    Re: Question about genetics guarantee

    Quote Originally Posted by Gerardo View Post
    .... How many clutches/eggs does it take to disprove a het?
    The formula is p to the nth power (pn) < 0.01.
    p = probability of not getting what you want from a single egg
    n = number of eggs

    Here's the easy way to calculate the formula. Using the calculator in Windows' Accessories folder, choose view --> scientific. Then enter the value of p, press the xy key, enter a value for n, and hit the <ENTER> key.

    Example 1: You have a normal looking ball python that could be heterozygous albino. You mate it to an albino ball python. You want albinos, and you do not want normal looking babies. The probability of getting an albino is 0.5, and the probability of getting a normal looking baby (p) is 0.5.

    Multiply 0.5 by 0.5 for as many times as it takes to get a number less than 0.01.
    In this case, 0.5 * 0.5 * 0.5 * 0.5 * 0.5 * 0.5 * 0.5 (or 0.5 to the seventh power) = 0.008 (rounded). In other words, seven normal looking snakes and no albino snakes has less than a 0.01 probability of occurring by chance.

    Example 2: You have a normal looking ball python that could be heterozygous albino. You mate it to a normal looking, het albino ball python. You want albinos, and you do not want normal looking babies. The probability of getting an albino is 0.25, and the probability of getting a normal looking baby (p) is 0.75.

    Multiply 0.75 by 0.75 for as many times as it takes to get a number less than 0.01. In this case, 0.75 to the seventeenth power = 0.008 (rounded). In other words, seventeen normal looking snakes and no albino snakes has less than a 0.01 probability of occurring by chance.

    The above assumes that albinos and nonalbinos have an equal chance of hatching. This is not always true. Or you may have plain bad luck. But it is the place to start, and almost all of the time it will give the right answer.

  2. The Following User Says Thank You to paulh For This Useful Post:

    wolfy-hound (12-18-2015)

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •  
Powered by vBadvanced CMPS v4.2.1