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  1. #9
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    Re: Proving a morph, kind of..?

    Here is the formula you want.

    P^n > 0.99

    P = probability of a single egg not producing a pastel
    ^ = to the power
    n = number of eggs.

    The probability of producing a pastel is 25% = 0.25. So P = 0.75.

    By a little trial and error with my calculator, n = 17. So you hatch 17 eggs. Every baby is normal, enchi, bright enchi or something other than a pastel. Then you have a 99.2% probability that the bright enchi parent is not a pastel enchi. More eggs raises the probability, but 99% is a good cutoff point.

    If one or more pastels hatch, then you can stop before 17 eggs, of course.

  2. The Following 2 Users Say Thank You to paulh For This Useful Post:

    Jonas@Balls2TheWall (11-17-2012),RoseyReps (11-17-2012)

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