A math problem...

[towelie4365]

0.292969% that 4 favorable and 1 unfavorable outcome happen. 0.39% is if 4 or 5 favorable outcomes happen.


Edit: Didn't see there was more than one page .

But here's another interesting thing: The probability that you would get 0 albinos is only 23.7%, meaning you have a 76.3% chance at getting one or more albinos with a het x het breeding . This is assuming a clutch of 5 eggs

[snakesRkewl]

awesome odds

2 seasons ago we bred a black pastel het ghost X albino and got 8 black pastels out of 9 eggs, pretty much my best clutch odds wise.

[swansonbb]

Thanks to all! The last hatchling crawled out of the egg Friday night. I can only upload cell pics until I find my camera cord..., but here you go.

[qegalpal]

WOW! GREAT odds, can I kiss the ring or rub your belly, lol.
I really NEED the odd Gods to be on my side...

[BHReptiles]

Thanks to all! The last hatchling crawled out of the egg Friday night. I can only upload cell pics until I find my camera cord..., but here you go.

WOW! Those are some clean, reduced, high contrast albinos! I'll just take those off your hands for you....

[gsarchie]

Your math doesn't make sense to me. By that same formula, if you had gotten four eggs then you would only have a 10% chance of getting an albino, because .25 X .75 X .75 X .75 = .105 X 100 = 10.5%. If you do every combination of .25 and .75 that you can, then you won't get all the way to 100%, only 96%.

[towelie4365]

Your math doesn't make sense to me. By that same formula, if you had gotten four eggs then you would only have a 10% chance of getting an albino, because .25 X .75 X .75 X .75 = .105 X 100 = 10.5%. If you do every combination of .25 and .75 that you can, then you won't get all the way to 100%, only 96%.

I explained it more here: http://ball-pythons.net/forums/showt...ble-recessives

You do have a 10.5% chance at getting ONE albino when looking at only one egg, so that's a 4*10.5%=42% (there are 4 different ways of getting one albino out of 4), but you also have a 6*(.75*.75*.25*.25)= 21% chance at getting two (there are 6 ways of getting two), and a 4*(.25³*.75)=4.68% chance at getting 3 (there are four ways to get 3), and a .25⁴=0.4% chance at getting 4 in a 4 egg clutch. Add those up and you get 68% chance, and if you find the chance you don't get one (.75⁴), you get 31.6% chance... which when you add those two together, you get 100% chance of all outcomes. I go into that in that thread I created in response to this

[BHReptiles]

I explained it more here: http://ball-pythons.net/forums/showt...ble-recessives

You do have a 10.5% chance at getting ONE albino when looking at only one egg, so that's a 4*10.5%=42% (there are 4 different ways of getting one albino out of 4), but you also have a 6*(.75*.75*.25*.25)= 21% chance at getting two (there are 6 ways of getting two), and a 4*(.25³*.75)=4.68% chance at getting 3 (there are four ways to get 3), and a .25⁴=0.4% chance at getting 4 in a 4 egg clutch. Add those up and you get 68% chance, and if you find the chance you don't get one (.75⁴), you get 31.6% chance... which when you add those two together, you get 100% chance of all outcomes. I go into that in that thread I created in response to this

x2.

Most people aren't very math savy. Please don't break your brain if you aren't into math D: We need good brains in this hobby.

[gsarchie]

I messed up when I only multilpied the ((.25*.25*.75*.75)*4) and not *6). As for being math savvy, it isn't that I'm not, it is just that I am rusty. I did well in bio-stats in college and had the highest grade in my calculus class. I've always loved math because it is simply logic and is black and white, right or wrong. That said, could we not multiply the (.29%*5) for the odds of getting 4 out of 5, since there are 5 ways to get 4 albinos out of 5 eggs? That would make the odds around 1.5% if I'm not mistaken.

[towelie4365]

Yep, that is correct. 0.29% would be that those specific eggs hatched that way, 1.5% chance that any combination results in 4 albinos