Like dr del said, either a snake is het for a recessive trait or it isn't, but say you did a het to het pairing, not all the babies are hets but you have no way of knowing which ones are and which ones aren't, so you have to label them as "Possible Hets".
Say you did this pairing:
Normal het. Albino X Normal het. Albino
When you work out the Punnett square, you'll be able to see that in a four-egg clutch two of the babies would be het for albino, one of them would be just normal and one of them would be albino.
That's all good and dandy if you're just using a genetics calculator and such, but if you actually hatch out the clutch, you can't decipher which babies that look normal are actually het and which ones are not, so you look at the theoretical number of hets in the clutch (2) over the number of babies that look normal in the clutch (3, being the two hets and one normal) and from that you get that all the babies have a 66% chance of being Het albino.
You therefore have a four-egg clutch with 3 normals 66% possible het for albino and one albino.
Hope this helped!
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