because I like arguing math:

My old post about !120 possible combinations given 60 base morphs is wrong.. I assumed !(2 x number of base morphs), given combinations for both heterozygous and homozygous expressions of the genes.. but that would only be correct if an animal could be both het and homo for the same morph (duh im stupid)

let's take a look at possible combinations if only one morph existed. Lets do albino.
normal
het albino
albino
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3 possible combinations
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let's take a look at possible combinations if just 2 morphs existed. For this example, I'll pick cinny and albino.

possible combinations:

normal
cinny (het for cinny gene)
super cinny (homo for cinny gene)
het albino
albino
cinny het albino
cinny albino
super cinny het albino
super cinny albino
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9 possible combinations
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again with 3 morphs: cinny, albino, and pastel

normal
cinny
super cinny
het albino
albino
pastel
super pastel
cinny het albino
cinny albino
cinny pastel
cinny super pastel
cinny pastel het albino
cinny pastel albino
cinny super pastel het albino
cinny super pastel albino
super cinny pastel
super cinny super pastel
super cinny het albino
super cinny albino
super cinny pastel het albino
super cinny pastel albino
super cinny super pastel het albino
super cinny super pastel albino
pastel het albino
pastel albino
super pastel het albino
pastel albino

Did I get them all?
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27 possible combinations
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Interesting.. this looks like it is going up by powers of 3..
Gawd it has been too long since I did any enumerative combinatorics, I'm busting my head right now to solve and prove how many possible combinations there are with 60 base morphs.. lol i'm such a nerd