Lesser bee X Silver Bullet

[Ladydragon]

okay... guess I was wrong. I guess I have to rereread the genetics sections to figure this out properly.

[GenePirate]

Thanks, Casey, for your vote of confidence.

Let me try to explain this further for everyone so that we're all on the same page.

Assuming Graziani and NERD are correct—which I do, then I would call the silver bullet CCPp (C=cinny, P=pastel, p=normal in place of second pastel locus). The lesser bee would be LlSs (L=lesser, l=normal in place of a second lesser gene, S=spider, s=normal gene where we’re assuming there is no second S, no homozygous spider.)

The silver bullet will always throw a cinny gene, plus either a pastel or a normal, so CP or Cp. The lesser bee will throw one of the following: LS, Ls, lS, ls. So you could end up with equal chances of each of these 8 combos:

CPLS, cinnamon queen bee
CPLs, cinnamon lesser pastel
CPlS, cinnamon bumble bee
CPls, pewter
CpLS, cinnamon lesser bee
CpLs, lesser cinnamon
CplS, cinnabee
Cpls, cinnamon

If you want to do your own Punnett, CP and Cp across the top (there are no other combos for these two traits), and the four LS combos down the side (2 x 4 = 8).

If you’re thinking black pastel in place of cinny, just substitute B for C, or whichever letter you choose, and rename as appropriate.

[muddoc]

If you want to do your own Punnett, CP and Cp across the top (there are no other combos for these two traits), and the four LS combos down the side (2 x 4 = 8).

If you’re thinking black pastel in place of cinny, just substitute B for C, or whichever letter you choose, and rename as appropriate.

Actually, if you wanted to draw a punnett square for a breeding that involves four genes, the square would be 16 by 16, and contain 256 squares. There will be many duplicates within the square, but that would be the proper way to do it, and the only way if each of those animals were containing parts of the four genes (much more important when dealing with recessives).

[GenePirate]

Actually, if you wanted to draw a punnett square for a breeding that involves four genes, the square would be 16 by 16, and contain 256 squares. There will be many duplicates within the square, but that would be the proper way to do it, and the only way if each of those animals were containing parts of the four genes (much more important when dealing with recessives).

Not necessary. Each animal only contains two unique traits each, and one of the parents can only donate one of two possible combinations. I wouldn't wish 256 squares on anyone, especially when the final ratios are the same in either case.