Re: 66% Double Hets question
By the snake being 66 percent DH that means there is a 66 percent chance of the snake carrying those genes. Does not necessarily mean it has either of the genes mentioned.
Re: 66% Double Hets question
Punnet squares only represent the possibility of a potential pairing so in theory a 100% het x 100% het means you would have a 1 in 4 chance of hitiing a visual morph then the other 3 out of 4 represent the potential.for the other snakes.2 of the 3 should hold the gene while the other does not hence 66% (2 out of 3) this is true for both genes so it 66% het x2 so yes statistically you would have less of a chance of inheriting both genes but its just much easier to say 66% double het meaning a non visual morph from 2 100% hets. I hope my rambling made sense and was somewhat helpful.
Re: 66% Double Hets question
Quote:
Originally Posted by
Ash
Let me know if I'm wrong about this one.
I've seen ads for "66% double hets", which I assume must have come from a pair of 100% double hets.
Shouldn't they really be 43.5% double hets?
Lets say that you breed a 100% double het lavender pied to another 100% double het. The odds that any normal-looking baby inherits the lavender gene at all is 66%. The odds that any normal-looking baby inherits the pied gene is also 66%. So the odds that they inherit both of them is less likely than just one or the other.
In statistics the odds that any two events occur together/after one another is found by multiplying the odds of each together. (.66)(.66) = .435
Right? I know it's not much of a difference, but still.
Yes, you are correct, and yes, 44% is much different than 66%.
Re: 66% Double Hets question
However, 66% DH can come from (for example) a double het axanthic ghost bred to an axanthic het for ghost.
Re: 66% Double Hets question
Quote:
Originally Posted by
GenePirate
However, 66% DH can come from (for example) a double het axanthic ghost bred to an axanthic het for ghost.
They would be 100% het axanthic and 66% het for ghost. Just to clarify
Re: 66% Double Hets question
Quote:
Originally Posted by
Freakie_frog
They would be 100% het axanthic and 66% het for ghost. Just to clarify
Exactly. That would be the 66% chance that you'd have both genes in the same animal.
Re: 66% Double Hets question
On the Punnit square it comes out with odds of 44% of the normals looking offspring of two double gets actually having "both" genes is correct.
The double Het breeding would end in the results of
6.25% Normal
12.5% Normal but being het for Gene A
12.5% Normal but being het for Gene B
25% Het for Gene A and Gene B
6.25% Visible Gene A "Not" het for Gene B
6.25% Visible Gene B "Not" het for Gene A
12.5% Visible Gene A het for Gene B
12.5% Visible Gene B het for Gene A
6.25% Visible Gene A and B (double morph)
Since we are only dealing with the animals that do not have a visible trait we can remove 43.75% of the odds leaving 56.25% of the offspring in the equation. If 56.25% of the off spring now equals 100% of the animals being dealt with the 25% for those truely being double het would equal 44.4% of the offspring being dealt with when done using ratios.
Re: 66% Double Hets question
Quote:
Originally Posted by
GenePirate
However, 66% DH can come from (for example) a double het axanthic ghost bred to an axanthic het for ghost.
not 'DH' no...
Quote:
Originally Posted by
GenePirate
Exactly. That would be the 66% chance that you'd have both genes in the same animal.
correct, but - that would be 'mis-labeling' the animal
Quote:
Originally Posted by
Freakie_frog
They would be 100% het axanthic and 66% het for ghost. Just to clarify
this is correct...
Re: 66% Double Hets question
here is the easiest way to look at it..
when breeding a 100% het x 100% het you get
25% normals
50% het's
25% homo
Since you can't tell the normals for the hets 75% of the clutch is normal looking.
So of the you take 100% of the normal looking animals and since they were statically 75% of the total clutch you divide 100/3 this gives you 33.33%. So say you get 3 normals each normal on its own has a 33.33 % chance at being normal this means that of the 75% of original 100% (or 4 possible outcomes) 2 of them will be 100% het's.
So out of the 3 normal looking outcomes or 100% of the normal looking animals you subtract the 33.33% chance of it being just a normal and your left with 66.66% chance each animal will be a het.
Re: 66% Double Hets question
Quote:
Originally Posted by
alan1
not 'DH' no...
Uh, yes.
Re: 66% Double Hets question
Quote:
Originally Posted by
alan1
correct, but - that would be 'mis-labeling' the animal
Of course, but it is a true statement that there would be a 66% chance that the animal was het for both traits in that hypothetical circumstance. This appears to be the only way that the seller (mentioned in the OP's post) could be telling the truth, however incomplete, about his/her 66% double hets. Breeding a DH to a DH will not get 66% DHs. This is what the OP was concerned about.
Re: 66% Double Hets question
Quote:
Originally Posted by
GenePirate
Of course, but it is a true statement that there would be a 66% chance that the animal was het for both traits in that hypothetical circumstance. This appears to be the only way that the seller (mentioned in the OP's post) could be telling the truth, however incomplete, about his/her 66% double hets. Breeding a DH to a DH will not get 66% DHs. This is what the OP was concerned about.
I have a question. In the breeding of DH to DH would the odds be greater than 66% that you would at least receive one of the mutations (regardless of which one it is) in the animal, or would it stay at 66%. What is the calculation to arrive at the figure.
Re: 66% Double Hets question
Quote:
Originally Posted by
tonkatoyman
I have a question. In the breeding of DH to DH would the odds be greater than 66% that you would at least receive one of the mutations (regardless of which one it is) in the animal, or would it stay at 66%. What is the calculation to arrive at the figure.
As with any DH to DH breeding statically the odds are Very GOOD..i.e. breeding Pewter X Pewter still give's each animal that isn't a Double Homo a 66% chance of being a Het for both traits which means in something like a Pewter x Pewter breeding each egg only has a 6.25% chance at being a normal..which means there is a 93.75% chance that every animal will carry at least one copy of some Morph gene. :D
Re: 66% Double Hets question
Quote:
Originally Posted by
Freakie_frog
As with any DH to DH breeding the statically the odds are the same..i.e. breeding Pewter X Pewter still give's each animal that isn't a Double Homo a 66% chance of being a Het for both traits which means in something like a Pewter x Pewter breeding each egg only has a 6.25% chance at being a normal..which means there is a 93.75% chance that every animal will carry at least one copy of some Morph gene. :D
WOW bought him books and sent him to school, and he read them instead of eating them. LOL :gj:
Re: 66% Double Hets question
Quote:
Originally Posted by
tonkatoyman
WOW bought him books and sent him to school, and he read them instead of eating them. LOL :gj:
Nobody said I still didn't eat them..just read them first.
Re: 66% Double Hets question
Quote:
Originally Posted by
GenePirate
Exactly. That would be the 66% chance that you'd have both genes in the same animal.
I think she's right on that one. Given the fact that the animal definitely carries one gene, there remains a 66% chance it carries the other too. So, there's a 66% chance that it carries both, otherwise it only carries one. I think that's the only situation in which the term '66% possible double het' could be kinda true.
I doubt sellers are gonna stop calling their possible double hets "66%" any time soon either way, regardless of how they were produced. At least the consumer can know better :-)
