Understanding HETS and POSSIBLE HETS

Morning Everyone - I wanted to get a better understanding of Recessive Genetics in terms of HETS and POSSIBLE HET percentages. I have seen 33% 50% 66% Possible Het and I'm really not too sure where those numbers come from or what combination of HET and PH pairings create them. I understand that if you breed a visual recessive snake you get 100% HETS just not sure about the below examples. Help, thanks!!

Normal HET x Normal HET =
Normal HET x Normal PH =
Normal PH x Normal PH =

Hi,

Well the snake is either 100% het or it isn't.

The poss hets are simply the chance that it will be 100% het.

So you can try and quantify the chance it is or not but that is about all the info is worth.


dr del

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Originally Posted by dr del

Well the snake is either 100% het or it isn't.

The poss hets are simply the chance that it will be 100% het.

So you can try and quantify the chance it is or not but that is about all the info is worth.

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Hey Derek - Thanks for the info. I understand that they are HET or they aren't, just wasn't sure how some came up with the advertised percentages of possible hets.

Like dr del said, either a snake is het for a recessive trait or it isn't, but say you did a het to het pairing, not all the babies are hets but you have no way of knowing which ones are and which ones aren't, so you have to label them as "Possible Hets".

Say you did this pairing:
Normal het. Albino X Normal het. Albino

When you work out the Punnett square, you'll be able to see that in a four-egg clutch two of the babies would be het for albino, one of them would be just normal and one of them would be albino.

That's all good and dandy if you're just using a genetics calculator and such, but if you actually hatch out the clutch, you can't decipher which babies that look normal are actually het and which ones are not, so you look at the theoretical number of hets in the clutch (2) over the number of babies that look normal in the clutch (3, being the two hets and one normal) and from that you get that all the babies have a 66% chance of being Het albino.

You therefore have a four-egg clutch with 3 normals 66% possible het for albino and one albino.

Hope this helped!

What about this?

Super Pastel x Spider = what would be the outcome?

:cool:

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Originally Posted by Alexandra V

Say you did this pairing:
Normal het. Albino X Normal het. Albino

When you work out the Punnett square, you'll be able to see that in a four-egg clutch two of the babies would be het for albino, one of them would be just normal and one of them would be albino.

That's all good and dandy if you're just using a genetics calculator and such, but if you actually hatch out the clutch, you can't decipher which babies that look normal are actually het and which ones are not, so you look at the theoretical number of hets in the clutch (2) over the number of babies that look normal in the clutch (3, being the two hets and one normal) and from that you get that all the babies have a 66% chance of being Het albino.

You therefore have a four-egg clutch with 3 normals 66% possible het for albino and one albino.

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Yuppers, just what I was looking for. Thanks for the help!

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Originally Posted by Johnny84

What about this?

Super Pastel x Spider = what would be the outcome?

:cool:

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Half of the babies would be bumblebees (pastel spider) and the other half would be pastels. Neither of those traits are recessive, so you'd be able to tell which snake is which morph just by looking at them.

50% Pastel
50% Bumblebee

Quote:

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Originally Posted by Alexandra V

Half of the babies would be bumblebees (pastel spider) and the other half would be pastels. Neither of those traits are recessive, so you'd be able to tell which snake is which morph just by looking at them.

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Ok...thats what I thought! I am planning on to pick up a Pastel and a Spider from a friend! Thanks!:cool:

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Originally Posted by el8ch

Best outcome = Killer-Bee

(Double Dominent Gene)

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That is what I am hoping! But...anyone know the percentage of chance out of say 4 eggs?

Super Pastel x Spider = ??