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  1. #1
    Registered User irock_2006's Avatar
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    Question 100% Het. Male X Reg. Female

    I am in no means looking to start breeding soon...I just have a question, I guess I am not entirely sure how it works??
    I notice on alot of breeder's websites, on the price list of, let's say albino ball pythons, the 100% Het. Males are alot cheaper than the 100% Het. Females...is there less of a chance of getting the albino with only the Het. Male?
    I ask because I have a Regular Female...if I bred her with a 100% Het. Male of "some morph"...what would I get?
    This may sound ridiculous, but I am just wondering...any help would be appreciated.

    Josh and Ocho
    1.1 Ball Python Female-Ocho(8mo.) Male-Ibo(2mo.)

  2. #2
    BPnet Veteran ThyTempest's Avatar
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    Re: 100% Het. Male X Reg. Female

    100% het x normal yields all 50% poss hets.

    Females are more expensive in general since you can have a bunch of het or morph females all paired with one male.
    -Austin
    0.8 Normal 1.0 Pastel 0.0.1 Spider
    1.1 Het Kahl BCI-08's-FS/T
    1.0 Hypo Citrus Beardie (Citrón)
    0.1 Citrus Beardie (Tang)
    0.0.1 Rose Hair Tarantula (Rose)
    0.1 Himalayan Cat (Meredith)
    0.2 Persian Cats (Madison and Myrtle)
    1.0 Shih-Tzu (Gizmo) 0.1 Lhasa-Apso (Lana)
    Rats, ASF's, Turks & Dubias.

  3. #3
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    Re: 100% Het. Male X Reg. Female

    From what I understand if you breed a resesive trait (albino) carier with a non carier (normal) you get mostly normal with a small chance of being het.

    100%Het Albino + Normal= 50%+/- Het, 50% normal
    But I'm not totaly sure. But from what I have heard you would have to breed the children back to proove out any true Hets

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