This is interesting, because I just sent an e-mail to someone advertising 50% double het pied/albino. His animals are actually 25% probable double hets.

In this example (100% probable het pied x 100% probable het albino), the outcome is the same. Each offspring would be 50% probable het for EACH trait, not both. There are four possible outcomes -

PA (double het)
Pa (het pied)
pA (het albino)
pa (normal)

1 in 4 chance of double het = 25%.

So, 100% het pied x 100% het albino = 25% probable double het.

Steve

edit - too slow. Freakie beat me to it!

Quote Originally Posted by Mezclado_Reps
With 100% het pied to 100% het albino, each baby would look normal, but be 50% double possible het. Theoretically, 1 normal to 1 double het, to 1 het albino to 1 het pied. Only way to get an albino pied is to have both parents either showing or carrying both traits.
both of these are recessive traits, so if you hear any other morphs that are recessive, they follow these rules. I suggest reading up on Punnet squares and the NERD and other websites that have genetics FAQ.