If you meant "hets" and not "gets"... as in:
Then the breakdown is as follows:
Het Pied Male x Het Pied Female = Each animal will pass on one copy of the Pied gene to 50% of the offspring, and no copies of the Pied gene to 50% of the offspring. Some will overlap, some will not. This gives you a breakdown of...
- 25% NORMALS (both parents passed on no copies of the Pied gene)
- 25% VISUAL Pieds (both parents passed on one copy of the Pied gene, resulting in a baby with two copies of the gene, giving the visual effect)
- 50% HET Pieds (one parent passed on one copy of the Pied gene, one parent passed on no copies of the Pied gene, so the baby carries the gene, but does not show it)
The problem now becomes: which babies are HET, and which are NORMAL?
You might be able to make a guess by looking for markers - but remember, these are only clues, and not guarantees. As such, each baby that does not display the visual has a 66% chance of being HET, meaning those are the odds that it carries the hidden gene. :)