I think you're confusing a few different terms. The 1.0/0.1 refers to the sex of the snake. 1.0 is male, 0.1 is female, and 0.0.1 is unsexed. So, if I have 1.2 66% possible het pieds, that means that I have 1 male and 2 female balls that have a 66% chance of carrying the piebald gene.
Someone correct me if I'm wrong, but I believe if you have two visually pied (or whatever recessive gene you're breeding out) parents, then all of the offspring that look normal are 100% het pied. If you have two het parents, you may get a clutch with a few visual pieds and normal looking offspring. Only 66% of those normals will carry the gene. If you breed a het pied to a normal, all of your hatchlings will look normal, but only 50% of them would be het... meaning that each hatchling has a 50% chance of carrying the pied gene.
Here is a quick link I found that talks about genetics and percentages: http://www.arbreptiles.com/genetics101.shtml
There are also examples of the punnet square on that link.
Hope that helped!
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