Not necessarily, because there does not seem to be any agouti here, so if those guys are pink eyed, they would not be argente, because argente is pink eyed agouti.
But they are also not pink eyed black, because that is champagne (or called lilac in the UK a/a p/p). What they most likely are, is pink eyed recessive yellow. Which is (a/a e/e p/p).
The 'black eyed champagne is probably (a/a b/b e/e) or chocolate + recessive yellow. It would be champagne if it were (a/a b/b p/p) pink eye is what makes it a champagne.
The browns are chocolate (a/a b/b)
The blacks are ... black (a/a)
And the yellows are either: Recessive yellow (a/a e/e) or Pink eyed recessive yellow (a/a e/e p/p)
AND THAT'S MY FINAL ANSWER. lol
Oh yeah and they're all (s/s) recessive piebald
a = black
A = agouti
b = chocolate
B = no chocolate
e = recessive yellow
E = no recessive yellow
p = pink eye (not albino, which is c/c)
P = no pink eye dilution
s = piebald
S = not piebald
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