Don't apologize, that's what these forums are for!
Every recessive gene is a mutation all of it's own and effects the genetics differently. In short you cannot breed two seperate recessive trait animals and expect to get both recessive genes to be visual in the offspring.
If you breed a visual example of a recessive mutation to a normal you will get 100% of the offspring being normal het. recessive.
I'll use Albino as an example;
Albino x Normal = 100% Normal het. Albino (non visual carrier for the albino gene)
Het. Albino x Normal = 50% normal, and 50% normal het. albino
Albino x Normal het. albino = 50% Albinos and 50% normal het. albino
Albino x Albino = 100% Albinos (Visual representations of the mutation)
Where is get's complicated is when you throw other recessive genes into the mix.
Again, I'll use albino as an example, but this time I will include the piebald gene.
If you breed;
Albino x Piebald = 100% Normal het for BOTH albino and piebald.
Now if you take one of those males and breed it back to the piebald mother you would get;
Het. Piebald, het. Albino x Piebald = 25% Piebald,
25% piebald het. albino,
25% normal het. piebald,
25% normal het. piebald het. albino
but you will never get a visual representation of the albino gene UNLESS you breed two siblings TOGETHER from the aforementioned pairing.
Long story short, you need BOTH parental animals to carry both recessive genes either visually or heterogeneously to produce visual offspring that show the traits of both recessive mutations.
Play around with the genetic calculator on WOPB, you'll have a blast and learn a lot.
http://www.worldofballpythons.com/wizard/
hope this helped/ wasn't too confusing.
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