Piebald het X normal?

[Scirlygirl]

What do you get if you breed 66% het piebald black pastel to a normal?

[snakesRkewl]

Black pastels and normals
If it proves to be a 100% het then the offspring would then be 50% pos hets.

[yzguy]

but all are technically 33% hets (which jumps to %50 if the het pied parent proves out).

[Spiritserpents]

No so, because the parent is either het or not. Therefore they are either 0% or 50%, there is no in-between.

[Pythonfriend]

No so, because the parent is either het or not. Therefore they are either 0% or 50%, there is no in-between.

except when you calculate the odds

you can say: "either this happens or that happens, nothing inbetween", or you calculate the odds. a lottery ticket either wins or it doesnt, thats one or zero, completely binary. and odds to win are 1 in 16 million, neither 1 nor 0, but something inbetween.

strictly speaking its either 100% hets or 0% hets, if you are so strict then explain how you arrived at 50%, thats clearly impossible, its either a het or it isnt

the OP would get 33% het pieds. which is a 33% chance for a 100% het pied and 66.7% chance to get a normal.

[Archimedes]

the OP would get 33% het pieds. which is a 33% chance for a 100% het pied and 66.7% chance to get a normal.

Correct. What this means is that there is a 33.3% chance that each baby is a het. The babies themselves are either 0% or 100%, but since the gene is nonvisual, there's no way of knowing which might be het and which are simply normals. This is why you see Possible Hets advertised. If there are no visual het markers, the animal is basically Normal Until Proven Het.


Sent from my cool hide

[Spiritserpents]

I still don't see why the number is 33%. The 66% comes from a punnet square of two adults both het, leaving 1 square as visual, 3 squares as non-visual, two of which are het. 66%.

You take that 66% het and breed it, well, it is either a carrier or not. So in its two potential punnets, bred to a non-het, you either get babies 0% het, or 50% het. If it is a carrier, the % chance for its offspring is 50%, not 33%.

[Pythonfriend]

I still don't see why the number is 33%. The 66% comes from a punnet square of two adults both het, leaving 1 square as visual, 3 squares as non-visual, two of which are het. 66%.

You take that 66% het and breed it, well, it is either a carrier or not. So in its two potential punnets, bred to a non-het, you either get babies 0% het, or 50% het. If it is a carrier, the % chance for its offspring is 50%, not 33%.

here you need to combine stochastics and the punnet square.

i think one correct way to use the punnet square for this breeding, 66% possible het to normal, would be: You make a split between 66% and 0%. then you need to write "66% possible het" into half of the squares, and "normal" into the other half of the squares. since they look similar, you average it out, and end up with 33% possible hets. (66% possible het still stands for: 66% chance to be a 100% het, 33% chance to be a normal).

or you make the square bigger, and turn the 66% into three rows: 2 rows with 100% het, one row with normal. in the end, two thirds of the squares will be filled with 50% hets, one third will be normals. averaging it out: (1/2 x 2/3) + (0 x 1/3) = 1/3 = 33%. Same result if you do it correctly.

basically what you do right now is you round the 0.66 to 1 in one of your inbetween steps.

[grcforce327]

Hell,just make the punnet square and cube!