Proving Dominant Traits

[Mike41793]

2) Yes, Cinny and Black-pastel can produce the super form I suppose, I have not seen that complex proved out though I may have missed it. If that's the case then Cinny is indeed Co-dominate and that term can be held true.

Glad you enjoyed it!

A cinny x bp will give you a 25% chance at the super form which is an 8 ball. An 8 ball bred to a normal will give you 50% cinny and 50% bp. (according to WOBP).

That doesnt make sense to me. I would think it would be 25% normal, 25% cinny, 25% bp, 25% 8 ball...

Mike - If they do that's impressive, but will be next to impossible to prove out, it may very well be a weird situation with that possible super pin. Pinstripe x pinstripe is also one of those lethal combos when you cross into the super form. Otherwise we would have people selling morphs as "Proven Homozygous Pinstripe" etc. etc.

Yea true. Like i said it was just a rumour i heard on here one time before. Im not saying they do or dont

[reptileexperts]

A cinny x bp will give you a 25% chance at the super form which is an 8 ball. An 8 ball bred to a normal will give you 50% cinny and 50% bp. (according to WOBP).

That doesnt make sense to me. I would think it would be 25% normal, 25% cinny, 25% bp, 25% 8 ball...

If you breed any super to a normal, you will never get a normal, because they will contribute on of the dominate genes, be it the C or BP gene from the super. The reason this is is because they are located on the same loci (location on the chromosome) so when it goes through its events and the chromtids are formed, it can ONLY pass on one of the genes, not both. It's different than if you take a Caramel Jaguar and bred it to a normal you would get 25% Caramel Jags because both of these genes are true co-dominates with the Homo Jag being lethal homo.

[Mike41793]

If you breed any super to a normal, you will never get a normal, because they will contribute on of the dominate genes, be it the C or BP gene from the super. The reason this is is because they are located on the same loci (location on the chromosome) so when it goes through its events and the chromtids are formed, it can ONLY pass on one of the genes, not both. It's different than if you take a Caramel Jaguar and bred it to a normal you would get 25% Caramel Jags because both of these genes are true co-dominates with the Homo Jag being lethal homo.

Yea but my point is that the cinny and bp are two diff morprhs yet they can make a super that produces no normals. Idk how much they differ then if thats obviously the case.

[WingedWolfPsion]

Yea but my point is that the cinny and bp are two diff morprhs yet they can make a super that produces no normals. Idk how much they differ then if thats obviously the case.

It's because they are two different mutations of the same gene (basically--yes, I know it's more complicated than that, but this will help make it understandable).

If you breed a cinnamon to a normal, it can pass on either the cinnamon gene, or the normal gene, right? The baby will then get a normal gene from its mother as well--she can only pass on a normal gene, because she has 2 of them. The baby gets one set of genes from mom, and one from dad--now it has a pair.

If you breed a cinny to a black pastel, and the cinny passes on its morph gene, and so does the black pastel, then the baby has one cinny morph gene, and one black pastel morph gene...but those two genes are in the same spot, so even though they are different mutations, the baby does not have a normal copy of that gene--just two different mutant copies, get it?

So when you breed it, it can only pass on one mutant copy, or the other mutant copy, because it doesn't have a normal copy.
As a result, each baby has a 50% chance to be cinnamon, and a 50% chance to be black pastel. It can't be both, because it only inherits one copy of that gene from the bp/cinny super.

Now, if you have a bumblebee, it has one copy of a pastel gene, and one normal gene in one spot, and then one copy of a spider gene, and normal gene in a DIFFERENT spot. So, it can pass on a pastel gene or normal gene in one spot, and a spider gene or normal gene in the other spot. Because they aren't mutations of the same gene, it can pass both the pastel and spider gene to its offspring, so it can have bumblebee offspring.