For those of you who like to study the genotypes of different morphs . . .
Does anyone know how the albino's recessive tyrosinase-negative (T-) allele and the sable's co-dominant hypermelanistic allele are related?
If these alleles are related to the same gene, then crossing an albino and super sable would yield a monohybrid. Containing only one albino allele, I would expect the offspring to look more like a sable or even a super sable due to its lacking a normal melanistic gene.
If these alleles pertain to different genes, a little Punnett square work shows that it would take a minimum of two generations of breeding, starting with a super sable and albino, to produce a double homozygous albino super sable (1:16 chance). You could increase your odds to 1:4, but you would have to wait for some F3 females to reach breeding age.
If anybody is still with me, what would this look like? Would it be mostly white, mostly yellow, mostly dark with white highlights? I think the sable is one of the more overlooked morphs, and I doubt this has ever been done. Share your ideas!