I think its an obvious choice, axanthic het pied x axanthic het pied. this leaves with a 1/4 chance of hitting the axanthic pied and the rest would all be axanthic poss hets. your always making a homozygous animal with the chance of a double homozygous (which i'm assuming is your goal)
pied x axanthic het pied yields you at best to make a pied het axanthic. which is a homozygous hetrozygous and you only make that 50% of the time.
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