Crossing with a normal

[DmD]

Hello everyone,

My name is David and I am from South Africa, I have been offered a list of Balls which are going to be imported. And I need to be make my mind up.

Firstly which would more dominant with regards to genes- A female or a male?

My Choices:

Mojave & Normal
Spider & Normal
Yellow Belly & Normal


Would the results be 50%/50%?
And can anyone explain Punnets Sqaure to me

Thanks,

David

[WingedWolfPsion]

There's no evidence that one gender has more 'dominant' genes than another. However, males generally take only 1 year to reach breeding maturity, and females generally take 3 years.

The results of all of the pairings you mentioned would be a 50% chance for each egg. (Either they inherit the mutant gene from one parent, or they do not).

Mojave, spider, and yellowbelly are all co-dominant, which means they are heterozygous. They have one mutant gene for color/pattern, and one normal gene for color/pattern. There is a 50% chance of their passing one or the other to their offspring. If they pass the mutant gene, the hatchling will be a mutant (it will get a normal gene from its normal parent, of course). If they pass the normal gene, the hatchling will be normal.

Here is a simple Punnett Square calculator:
http://www.changbioscience.com/genetics/punnett.html

Let's use Mojave as an example.

The mojave ball python would be coded as "Aa". 'A' is the mutant gene, and 'a' is the normal gene.
The normal parent would be coded as 'aa'--2 normal genes.

Put into the calculator, you get
Aa aa
Aa aa

So, 2 mojaves, 2 normals out of 4 total. A 50% chance.

[DmD]

Thanks WingedWolfPosion

[pedipalps]

Are spiders are dominant or co-dominant? Because there no super form of a spider unlike mojave and yellowbelly.