Quote Originally Posted by jsmorphs2 View Post
Well usually line breeding refers to a parent x offspring pairing. If you bred a double het albino/pied to an albino, for instance, the only visual morph you could produce would be an Albino. You would end up with:

Albinos
Albino Het Pieds
100% Het Albinos/50% Poss Het Pieds
100% Het Albino


You would need to breed double het x double het siblings (inbreeding) to have a 1 in 16 chance of producing albino/pieds. The offspring would be:

Albino/Pieds
Pieds
Albinos
Albinos 50% Het Pied
Pieds 50% Het Albino
50% Het Albinos
50% Het Pieds
50% Double Het Albino/Pied
Normals

If you wanted to avoid inbreeding you can produce your own double hets and hold back all the females then purchase a double het male from a different breeder.
The way you have it written out looks pretty confusing, and is a bit redundant because you are writing out both phenotypes as well as genotypes. For albino x dh albino pied, you can get:

2:4 Albinos 50% chance het Pied
2:4 Het Albinos 50% chance het Pied

For double het x double het, you can get:

9:16 66% chance het Albino, 66% chance het Pied (33% chance double het)
3:16 Albino 66% chance het Pied
3:16 Pied 66% chance het Albino
1:16 Albino Pied

As per OP's original question, I would suggest a pinstripe male to breed to the bumblebee female (or a pinstripe female to breed to the pastel if you would rather go for killerbees and lemon blasts than just going for spinner blasts, but that just boils down to personal preference). I wouldn't get a spider though, as you already have the bumblebee for that. If you go with the male pinstripe, I would also suggest breeding that to the normal female.