1.0 pied X 0.1 100% het pied????

[Twisted Reptiles]

You would get 50% of the clutch being het for Pied, 25% of the clutch being normal, and the other 25% of the clutch being Pied.

P= upper case dominant allele (PP= normal)
P= lower case recessive allele (pp= recessive)
Pp or pP= both upper and lower case alleles (Pp or pP= heterozygous)

100% het Pied x 100% het Pied

50%= heterozygous (alleles are Pp or pP)
25%= normal (alleles are PP)
25%= Piebald (alleles are pp)

Sorry Tiff but not so, there wouldn't be any normals. Because there is a homozygous pied involved all babies would be at a minimum 100% het pied. As others have stated, this is a 50/50 situation.