Recessive and co-dominant

[ScottyDsntKnow]

Those are projects. For something like an albino pied you would breed an albino to a pied, then raise up the children which are 100% het for both traits. Breeding these back together gives you a 1/16th shot at the albino pied.

[cinderbird]

Ok. Now, I understand that some of the really wild morphs are double recessives but how does one go about getting different/new morphs from co-dominant or dominant-gene hom BPs? Do you bred for secondary traits such as to get the difference between a black-eyed Lucy and a blue-eyed Lucy?

I guess the incredible new piebald morphs are double recessives? I just saw a pic of a "Panda Pied" on a thread about the Tampa show. WOW! Was that a project or just an accident?

You need to start off knowing which morphs, when combined, make what combinations (designer morphs).

The Black eyed leucistic (black eye w/ red pupil) is the homozygous fire morph. The Blue eyed leucistic (blue eye with i'm not exactly sure which color pupil, pinkish i think) is the "white snake complex" super. IE if you breed any of the following together, you have a chance to get a mostly white snake with blue eyes: mojaves, lesser platinums, butters. Vin russeo (sp?) het leucistic, maybe yellowbellies as well (i'm not 100% sure on those). So all those snakes can produce a white super and they are seperate morphs as of this moment. For more on the white snake complex.. theres info in other threads.

You can certinly selectivly breed to make brighter pastels, brighter orange albinos, darker het albinos, etc. But selective breeding will not be making you a new morph.