So I'm looking on genetic wizard, and if I have this down correct, you breed an axanthic to a pied and get all normal double hets. Then breed the double hets together (or to an outside double het) to get... 1/8 chance at axanthic pieds? And if you end up with a bunch of normals, would you list them as normal 33% het pied 33% het ax? Or 25%? Out of the 16 possibilities, there are 12 normal-looking possibilities, 4/12 would be het axanthic, 4/12 would be het pied. Or do you count the overall total (16) and it would be 4/16 het pied 4/16 het axanthic? I hope I'm making sense. Here's the genetics wizard link:

http://www.worldofballpythons.com/wi...female=30h,83h

TIA!