Quote Originally Posted by Wh00h0069 View Post
Thanks. I was actually thinking of creating a java applet that calculates for ball pythons, boas, corn snakes, and leopard geckos. It would take a while to figure out all of the different combinations, and names, as well as images of each one. However, I recently graduated with my Bachelors in Software Engineering, and I am looking for a fun project. I actually think that I have figured it out. I did a little research, and it is called branching. Correct me if I am wrong.

Albino x Het Albino:

.5 het albino
.5 albino

Hypo x normal

.5 wild type
.5 hypo

Put them together:

.5 het albino -> .5 wild type = .25 het albino
-> .5 hypo = .25 hypo het albino.5 albino -> wild type = .25 albino
-> = .25 hypo albino
Then if you wanted to add another morph, for example a pied

Pied x het pied

.5 het pied
.5 pied

.25 het albino -> .5 het pied = .125 double het pied albino
-> .5 pied = .125 pied het albino
.25 hypo het albino-> .5 het pied = .125 hypo double het pied albino
-> .5 pied = .125 hypo pied het albino
.25 albino-> .5 het pied = .125 albino het pied
-> .5 pied = .125 albino pied
.25 hypo albino-> .5 het pied = .125 hypo albino het pied
-> .5 pied = .125 hypo albino pied

And so forth, and so on.
Perhaps I'm misreading your math, but there's no way to get a hypo from the OP's pairing, since only one parent carries the gene. And with the added Pied example, are you assuming one parent is also a pied, and one is also het pied?