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Thread: Odd's

  1. #1
    They call me Emilius LOL Emilio's Avatar
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    Odd's

    Alright who's good with odd's calculations? What are the odd's of me getting a pied from a hetpied x hetpied breeding with 3 egg's? Math was never my favorite subject.. I know each egg has a 25% chance thats not what I'm looking for.
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    Re: Odd's

    My dad is a GENIUS. Listen to this: Each egg has a 75% normal, 25% pied, so thats 3:1 odds AGAINST you. Multiply by three (3 eggs), that's 9:3, 3:1 33% chance you'll get pied.

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  4. #3
    They call me Emilius LOL Emilio's Avatar
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    Re: Odd's

    And of course this is if she proves out. Either way more poss het girls are always good to.
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    Re: Odd's

    uhhhh goodluck lol



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    They call me Emilius LOL Emilio's Avatar
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    Re: Odd's

    It's exciting to say the least.
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    Re: Odd's

    Trust me, I'm horrible at math. But the ultimately wise Dad of mine is surprisingly good at it.

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    Re: Odd's

    So more than likely you may not get the pied but then I think you get 1 normal and 66 percent het pieds on average but since it is less than four eggs it will kind of be harder to calculate it.
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    Re: Odd's

    I'm gonna call it right now. One pied.
    --Walt

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    Re: Odd's

    I figure it a little different. Starts out the same, each egg from het pied X het pied has a 1/4 chance of being a homozygous pied so a 3/4 chance of not being visible pied. Then to find the odds of all three eggs not being pied you multiple the chance of each not being one together, so (3/4)^3 = 27/64 (so instead of multiplying by 3 you multiply by it's self three times, or how ever many eggs you have times). So if 27/64 is your odds of getting none then 37/64 is your chance of getting at least one. So I'm showing 57.8% chance of getting at least one pied from three eggs from het X het. So a good bit more likely to get at least one than to get none if you hatch all three eggs. However, as long as you are sure the parents are both hets all normal offspring are 66% chance hets.

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    Re: Odd's

    Quote Originally Posted by RandyRemington View Post
    I figure it a little different. Starts out the same, each egg from het pied X het pied has a 1/4 chance of being a homozygous pied so a 3/4 chance of not being visible pied. Then to find the odds of all three eggs not being pied you multiple the chance of each not being one together, so (3/4)^3 = 27/64 (so instead of multiplying by 3 you multiply by it's self three times, or how ever many eggs you have times). So if 27/64 is your odds of getting none then 37/64 is your chance of getting at least one. So I'm showing 57.8% chance of getting at least one pied from three eggs from het X het. So a good bit more likely to get at least one than to get none if you hatch all three eggs. However, as long as you are sure the parents are both hets all normal offspring are 66% chance hets.
    You just boggled my mind.

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