Pinstripe question

[Ginevive]

There is not a super form of the Pinstripe, is there? I don't think there is, but I wanted to be sure; thanks. I would guess that, like Spiders, a Pin x Pin breeding would yield all Pins.

[Freakie_frog]

Bingo

[Emilio]

I love pin's but since there is no super I'm patiently waiting til later to get mine.

[xdeus]

I heard that Brian Barczyk produced the super pin last year, but they didn't look much different from regular pins. It'll probably take another year to prove out completely, though.

[LadyOhh]

I asked him about it at Anahiem last year, and he said that it basically looked different out of the egg, but has gradually come to look like a regular pin.

Not sure what his plans for it are though.

[muddoc]

a Pin x Pin breeding would yield all Pins.

With that breeding, you still have a 25% chance of getting normals from each egg.

[Ginevive]

Thanks Darnit though.. wouldn't a super pin, or a super spider, be cool? Danged genetics sometimes.

[Gib]

Re: Pinstripe question
Quote:
Originally Posted by Ginevive View Post
a Pin x Pin breeding would yield all Pins.

With that breeding, you still have a 25% chance of getting normals from each egg.

Nope pin to pin will give you all pins

[Sputnik]

I asked him about it at Anahiem last year, and he said that it basically looked different out of the egg, but has gradually come to look like a regular pin.

Not sure what his plans for it are though.

Dom morph, when people try to produce a super out of a morph considered dominant.... they may tend to over hope for it to be a super when eggs hatch. That is dom to dom.... breeding.

I'd think like most morphs, you may see something look different when hatching and think/hope your onto something new only to see it turn out like the rest (So to speak) later. Just mother natures way of messing with your mind....LOL

[RandyRemington]

Like spider, the vast majority if not all pins are heterozygous for the pinstriped mutation. Heterozygous means they have one version of the gene with the pinstripe mutation and another version that is normal for pinstripe. When you breed two pins (or spiders) together each egg has a 25% chance of getting the normal version of the respective gene from both parents and being normal. There is also in theory a 25% chance of producing the homozygous version which gets the mutant version from both parents. Whether or not that animal would be super looking would determine the mutation type, either co-dominant or dominant.

If either mutation turns out to be dominant then the way that will be proven is when a homozygous pin or spider is bred to normals and produces a large number of only spiders or pins and no normals unlike the heterozygous animals which are expected to produce 50% normals in this breeding.