Breed axanthics

Hi people,

My axanthic female laying 4 eggs.
She was copulated with the male axanthic.

The axanthic morph is recessive, because I think that the babies can be:

25% (1 egg) Phenotype axanthic.
50% (2 eggs) Phenotype normal, het axanthic.
25% (1 egg) Pthenotype normal.

This is correct?

Axanthic X Axanthic = All Axanthic

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Originally Posted by GA_Ball_Pythons

Axanthic X Axanthic = All Axanthic

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Not true with rescessive genes. the original poster was correct.

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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No. If you breed an Axanthic to Axanthic all babies will be Axanthic

Now if they were het Axanthic the thread starter would be right.

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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Sry wrong rescessive x rescessive = All rescessive

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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Recessive x Recessive = ALL Recessives.

The original posters percentages were correct for a Het X Het breeding. All others are right with recessive X recessive 100% recessive.

Its not that recessive x recessive = all recessive, or that co-dom x co-dom does not.

For a particular trait -

Homozygous x Homozygous = all Homozygous

Homozygous x heterozygous =
50% Homozygous
50% Heterozygous

Heterozygous x Heterozygous =
25% Homozygous
50% Heterozygous
25% Normal

Heterozygous x Normal =
50% Heterozygous
50% Normal

REGARDLESS of whether the trait is recessive, co-dom or dominant.

So, if the OP's axanthics are homozygous, all babies will be homozygous (assuming the SAME LINE of axanthics). If they're hets, then his original assumptions are correct.

Steve

People,

Thank a lot.

Gabriel

Sorry...I forgot the last post: My BPs are 100% phenotype axanthic.

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Originally Posted by gafaled

Sorry...I forgot the last post: My BPs are 100% phenotype axanthic.

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Meaning they are hets?

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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Yes it is true if it was not I would not post it ;), this might help you understand a little better http://www.ballpython.ca/what_get/recessive.html

Meaning that look like axanthic, not only carry out genes.
Thank a lot.

Deborah,

This link is very good information for me.

Thank.

Quote:

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Originally Posted by gafaled

Meaning that look like axanthic, not only carry out genes.
Thank a lot.

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I bet you get all normals! Good luck..

Quote:

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Originally Posted by GA_Ball_Pythons

Yes it is true if it was not I would not post it ;), this might help you understand a little better http://www.ballpython.ca/what_get/recessive.html

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Are you sure? What if I breed a VPI Axanthic to a Snakekeeper Axanthic? Joliff? Nerd? Other new line?

I think I understand what you're trying to say... that a HOMOZYGOUS Axanthic bred to a HOMOZYGOUS Axanthic will yield all Axanthics. That is true as long as the snakes are from compatible lines.

Recessive X Recessive does not necessarily = Recessive.
If I breed a homozygous Axanthic to a homozygous Albino (both recessive), I'm not getting snows or albinos or axanthics. I will get double hets, though.

Axanthic X Axanthic does not necessarily = Axanthic.
If I breed a VPI Axanthic to a Snakekeeper Axanthic, I'm not getting Axanthics. double hets, yes... Axanthics, no.

Steve

Here is examples of the punnett squares of all possible outcomes from the same line of axanthic

axanthics allies= xx
Het Axanthics allies= Xx or Nx
wild type allies= NN

so axanthic x axanthic=
___x__x_
x |xx|xx|
x |xx|xx|

which means 100% visible axanthics


or 2 100% het axantics =
___N__x_
N|NN|Nx|
x|Nx|xx|

which = 25% wild type NN , 50% Het axanthics Nx, 25% axanthics xx


or a 100% het x axanthic=
___N__x_
x|Nx|xx|
x|Nx|xx|

which = 50% het axanthic Nx & 50% axanthic xx

or axanthic x wild type =
___x__x_
N|Nx|Nx|
N|Nx|Nx|

which = 100% het axanthic Nx

Last het axanthic x wild type=
___N__x_
N|NN|Nx|
N|NN|Nx|

Now these will all appear normal the odds are 50% het Nx & 50% normal but all babies would be know as 50% possible het

hope these helps and doesn't confuse you writing punnett squares on the forum is kinda hard :D

what if it was a pastel to a pastel? or a pastel to a super?

or do you just look at a pastel as being a het for super pastel?

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Originally Posted by claytonfaulkner

what if it was a pastel to a pastel? or a pastel to a super?

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As I mentioned in my first response in this thread, it makes no difference whether we're talking about recessive, co-dom, or dominant. The genetics work the same. The only difference is the visual result.

So, if a het Axanthic x het Axanthic =
25% homozygous Axanthic
50% het Axanthic
25% Normal

then

Pastel (heterozygous) x Pastel (heterozyous) =
25% Super Pastel (homozygous)
50% Pastel (heterozygous)
25% Normal

or

Pastel (heterozygous) x Super Pastel (homozygous) =
50% Super Pastel (homozygous)
50% Pastel (heterozygous)

Look at travisjara's post above, showing the punnet squares for axanthics, and plug in Pastel for het axanthic, and Super Pastel for Axanthic. The results will be the same. Again, the only difference is visual expression. In other words, where he said that het axanthics look normal, heterozygous Pastels do NOT look normal. Therefore, there would be no "50% probable het Pastels".

Steve