I have a simple question...

Somewhere in the near future im looking to buy a male boa for my beautiful female......if the male is a 100% albino 50% possible het anery would i get any morphs or would i then have to breed the offspring to something else to produce a morph ?

I went ahead and moved this to the Boa section, even though this is a genetics question. ;)

Is your female normal? If so, then you would not produce any morphs. Your female would have to be het albino as well. (assuming albino is a simple recessive trait in boas) You would produce normal babies that had a 50% chance of being het for albino.

Ya brandon, We need more info on your female genetic wise. When you breed 100% het to a 100% het you get
1/4 homo(visable morph
1/2 het
1/4 normal
Therefore making 66% hets because you have a 2 out of 3 chance of picking out a het from the litter.

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Originally Posted by Pork Chops N' Corn Bread

When you breed 100% het to a 100% het you get
1/4 homo(visable morph
1/2 het
1/4 normal
Therefore making 66% hets because you have a 2 out of 3 chance of picking out a het from the litter.

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you also have to remeber that, that's just statistics. 1/4 of the clutch is not always going to be a visible morph, same with 1/4 of it being normal or 1/2 of it being heterozygous.

Brandon, if your female is normal the statistics say half of the litter will be normal and half of the litter will be heterozygous for albinism (and 25% het for anery? (tell me is thats correct))

check this out. http://ballpythons.ca/genetics.html since it is a ball python page some of the mutations on the list may not be the same as far as recessive, co-dominant, or dominant with boas but it still works the same.

If one of them is normal and 1 is 100% het albino and 50% het anery, 1/2 of the littler will be het albino, half will be normal, you won't know if anyof them are het anery until you prove out the 50% het anery. Remember, 50% is just a way of saying 1 out of 2 will be het, therefore you have a 50% chance of one of the "normal" babies being 100% het.

you have a 25% chance for each hatchling to be het anery. i already knew that i just didnt know if it was called 25% het anery.;) :cool:

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If one of them is normal and 1 is 100% het albino and 50% het anery, 1/2 of the littler will be het albino, half will be normal

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that is incorrect. that's just statistics, its not definite. all of them can be normals or all of them can be het albino.

my head hurts... :rolleye2:

I second that! lol


(You did post A "simple" question, right)?!?!?;) joke...

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Originally Posted by Brandon.O

would i get any morphs or would i then have to breed the offspring to something else to produce a morph ?

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i forgot this.

you would have to breed the offspring back to the male and if you're lucky one of the offspring you bred to the male would be het for albinism and (again) statistics say for every 4 hatchlings you will get 1 albino, 2 heterozygous animals, and one normal. again, thats not definite.

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Originally Posted by mr~python

that is incorrect. that's just statistics, its not definite. all of them can be normals or all of them can be het albino.

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Just curious, where did you see that at?

im not sure. it's been a long time since i knew that. sorry, can't help you there. do you think im lieing?

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Originally Posted by mr~python

im not sure. it's been a long time since i knew that. sorry, can't help you there. do you think im lieing?

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Lieing? No Maybe a bit confusing
Can you explain this to me better?

"that is incorrect. that's just statistics, its not definite. all of them can be normals or all of them can be het albino."

Marshall's saying that, because even with the statistics, each baby has their own chance of being one or the other. .....Say you have four babies--just because the first one is one of the 25% normal, doesn't mean that another baby CAN'T be a normal. The punnet square will tell you the odds in a perfect world, but since you can't choose which gamete would give you het vs. which one would give you albino or normal, it's just to help figure the probabilities of what the babies could be.

It's not like the lottery, that when the number 47 is chosen, it can't be chosen again for that same drawing. Each baby has it's own 1 in 4 chance of being either normal OR albino.

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Originally Posted by sweety314

Marshall's saying that, because even with the statistics, each baby has their own chance of being one or the other. .....Say you have four babies--just because the first one is one of the 25% normal, doesn't mean that another baby CAN'T be a normal. The punnet square will tell you the odds in a perfect world, but since you can't choose which gamete would give you het vs. which one would give you albino or normal, it's just to help figure the probabilities of what the babies could be.

It's not like the lottery, that when the number 47 is chosen, it can't be chosen again for that same drawing. Each baby has it's own 1 in 4 chance of being either normal OR albino.

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That cleared up nothing in my mind....
thanks anyways

Hmmmmmmm Okay.....If you have 25 numbers in a lottery, you have 1/25 of getting the 1, 1/25 of getting the 2 and once that number's chosen, you can't choose it again until a new lottery drawing.


Genes are different. When a gene splits, it can be either the a or the A (if the snake is Aa). But once that a or A gene is used up for one baby in the litter, there are still other a's or A's available for the other babies in the litter. So each snake has it's OWN chance of being either a or A.

Does that help more?

So lets put this in these terms
You breed a het albino to a normal. You get 4 babies(not possible in redtails I know).
2 would be het
2 would be normal therefore making 50% POS het albino babies

You breed a 100% het albino to a 100% het albino and you have 4 babies(Again not possible in rtb).
1 would be albino
2 would be het
1 would be normal therefore making 66% hets

Correct?

Yes, because until you crossed your AA (normal) to an albino, you wouldn't be able to prove that it's NOT a possible het carrier of an "a" gene. If when crossing to your albino you DID get an albino, then you know that your "normal" is actually het.

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Originally Posted by sweety314

Yes, because until you crossed your AA (normal) to an albino, you wouldn't be able to prove that it's NOT a possible het carrier of an "a" gene. If when crossing to your albino you DID get an albino, then you know that your "normal" is actually het.

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Were talking about a Het Albino to a normal correct?

Yes, but wouldn't you eventually want to prove out your het? In order to do that in the fewest number of generations, you'll have to cross back to an albino (for a earlier result).

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Originally Posted by Pork Chops N' Corn Bread

So lets put this in these terms
You breed a het albino to a normal. You get 4 babies(not possible in redtails I know).
2 would be het
2 would be normal therefore making 50% POS het albino babies

You breed a 100% het albino to a 100% het albino and you have 4 babies(Again not possible in rtb).
1 would be albino
2 would be het
1 would be normal therefore making 66% hets

Correct?

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no, that is not correct.

you breed a het albino to a normal:
each baby has a fifty percent chance of being het (2/4 = 50%)
each baby also has a fifty percent chance of being normal.
now, this doesn't mean out of four babys 2 will be normal and 2 will be het, it just means each baby has a 50% chance of being normal OR heterozygous. 3 babys could be normal and one could be heterozygous, etc., etc.

now, you breed a 100% het. albino too another 100% het. albino:
each baby has a 25% chance being an albino, 50% chance of being het and a 25% chance of being normal. its all about chance, and sweety is right when she says its like the lottery.

All this talk of numbers has me hungry. Anyone want to come over for lunch today? lol

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Originally Posted by Pork Chops N' Corn Bread

All this talk of numbers has me hungry. Anyone want to come over for lunch today? lol

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so do you understand now?