Are there different albino and pied lines?

I was just wondering for when I am able to expand my collection for breeding. Lets say, instead of picking up 1.2 het pieds or albinos from a breeder, I pick up the 0.2 first, then a year or so after that I buy 1.0 het from a different breeder.

This wouldn't make a difference would it? As far as I know their aren't different lines. I could be totally off though. I know that most (if any) axanthic lines, some ghost lines, caramel and ultramel, and albino and lavender albinos are not compatible. Thats why I am not asking about them.

Now that I mentioned lavender albinos, are there any different lines with them as well?

if different "lines" arn't compatible, their different morphs all together.

but to answer your question, no there are not different lines of albino or pied. Lav albino is a completely different morph.

Sorta off topic but similar, what would happen if you bred a Pied to an Albino?

Alrighty. Thank you :D

And SnakeKB, 100% het for both traits I believe if your talking visuals.

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Originally Posted by SnakeKB

Sorta off topic but similar, what would happen if you bred a Pied to an Albino?

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That would only get you a het pied/het albino since they are recissive. To get an albino pied, you would need two snakes with both genes.
For example: pied het albino x albino het pied
Alibino pied x albino pied
Het albino het pied x het albino het pied
And so on...you would need both recessive genes to be passed to the offspring for both to be visable. Otherwise you may see one morph or the other, or a normal look poss. Het of either or both traits

But do you get a full morph like a Pied Albino? I just found a breeder that has what im talking about. Wants 25k for it. Pretty nice looking.

http://www.roussisreptiles.com/image...2009%20148.jpg

Sorry my last post was a little late. I understand now.

If you were to breed two visual recessive genes together, you will get all 100% het. offspring. However, if you are to breed 100% het. offspring together, you will only get 50% het. offspring.

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Originally Posted by bsash

If you were to breed two visual recessive genes together, you will get all 100% het. offspring. However, if you are to breed 100% het. offspring together, you will only get 50% het. offspring.

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66% not 50%

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Originally Posted by OhhWatALoser

66% not 50%

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Yes, I meant 66% thanks for catching that.

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Originally Posted by OhhWatALoser

if different "lines" arn't compatible, their different morphs all together.

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Yeah, but we refer to VPI, TSK, and Joliff axanthics as different "lines". And there are plenty of both incompatible and compatible "lines" for ghosts/hypos.

To answer the original question: All pied and lavender albino "lines" thus far have been compatible with each other. Most pieds are "Kahl" line, originating from a small breeder group of wild caught specimens that was proven genetic by Pete Kahl in '97... but there been other imported animals since then, and at least one example of piebalds popping out of unknown hets in an unrelated collection, ie. the "Kobylka-line pieds".

I don't know as much about the different lavender albino lines or the captive history of the morph. There have been plenty of imported wild-caught and captive-hatched animal, and they've all been proven compatible with existing lavender albino "lines", but the only one that I've seen a lot of talk about is the selectively-bred, high-color "Excalibur" line.

I think as people become more concerned with inbreeding of recessive traits, particularly in association with double-recessive morphs like dreamsicles, you'll see a lot more attention paid to the different wild-caught "lines".

... I don't know how I read "albino" as "lavender albino". Some kinda Freudian slip... anyway, what everybody said about albino vs. lavender vs. caramel vs. ultramel. I know bumpkus about the different "plain-old" albino lines, other than Bob Clark proved them out originally, but most of those animal were stolen.