Lookng for another morph

Hey guys, new to the forum here but not new to snakes. Tomorrow I'm heading to the SC show and looking to pick up another BP. Nothing too freaky, I was thinking about a Spider or a Pinstripe, add some dominant traits into my mix. Currently I have 0.1 Piebald, 0.1 Bumblebee, 0.1 Normal, 1.0 Albino and a 1.0 Pastel. Would either of the 2 I mentioned, in your opinion be a good match for my collection combo for breeding? And would you suggest a male or a female?

Also I'm still unclear as to how the recessive trait works, if I breed my male albino to my female piebald, will it yield all hets or will I get any visuals ie: albino piebalds?

Sorry for all the questions in one post but as you can tell by my sig I mostly deal in arboreal snakes and what you see is pretty much what you get with the parents.

Welcome to the forum!!!!!!!! I am not the best person to answer your questions but i will take a stab at some of it. When you cross albino and a pied you will get possible double het babies. I also think you can get single hets for albino and piebald. Someone else with more knowledge will chime in im sure!!

Albino x Piebald = 100% DH

None of the offspring will be visual.

Also it is better to have morph females, because males can do the deed more than once. :gj:

i would get the pin since you have a bee already i would also get a mojo or if you have the money a lesser or butter. if you breed your albino to your pied all the offsprings will be double het albino pied

Thanks for clearing that up guys!!! I told you i was lost when it came to recessive's lol.

So then the dble hets would have to be line bred to get the visual?

Quote:

---

Originally Posted by AdamM

So then the dble hets would have to be line bred to get the visual?

---

Well usually line breeding refers to a parent x offspring pairing. If you bred a double het albino/pied to an albino, for instance, the only visual morph you could produce would be an Albino. You would end up with:

Albinos
Albino Het Pieds
100% Het Albinos/50% Poss Het Pieds
100% Het Albino


You would need to breed double het x double het siblings (inbreeding) to have a 1 in 16 chance of producing albino/pieds. The offspring would be:

Albino/Pieds
Pieds
Albinos
Albinos 50% Het Pied
Pieds 50% Het Albino
50% Het Albinos
50% Het Pieds
50% Double Het Albino/Pied
Normals

If you wanted to avoid inbreeding you can produce your own double hets and hold back all the females then purchase a double het male from a different breeder.

Quote:

---

Originally Posted by jsmorphs2

Well usually line breeding refers to a parent x offspring pairing. If you bred a double het albino/pied to an albino, for instance, the only visual morph you could produce would be an Albino. You would end up with:

Albinos
Albino Het Pieds
100% Het Albinos/50% Poss Het Pieds
100% Het Albino


You would need to breed double het x double het siblings (inbreeding) to have a 1 in 16 chance of producing albino/pieds. The offspring would be:

Albino/Pieds
Pieds
Albinos
Albinos 50% Het Pied
Pieds 50% Het Albino
50% Het Albinos
50% Het Pieds
50% Double Het Albino/Pied
Normals

If you wanted to avoid inbreeding you can produce your own double hets and hold back all the females then purchase a double het male from a different breeder.

---

Alright thanks for clearing that up some. But I still have time to figure it out, my piebald and albino are early 09's. I tell you the complications of figuring out what to cross with what is harder then hatching out Chondropythons lol.

Quote:

---

Originally Posted by jsmorphs2

Well usually line breeding refers to a parent x offspring pairing. If you bred a double het albino/pied to an albino, for instance, the only visual morph you could produce would be an Albino. You would end up with:

Albinos
Albino Het Pieds
100% Het Albinos/50% Poss Het Pieds
100% Het Albino


You would need to breed double het x double het siblings (inbreeding) to have a 1 in 16 chance of producing albino/pieds. The offspring would be:

Albino/Pieds
Pieds
Albinos
Albinos 50% Het Pied
Pieds 50% Het Albino
50% Het Albinos
50% Het Pieds
50% Double Het Albino/Pied
Normals

If you wanted to avoid inbreeding you can produce your own double hets and hold back all the females then purchase a double het male from a different breeder.

---

The way you have it written out looks pretty confusing, and is a bit redundant because you are writing out both phenotypes as well as genotypes. For albino x dh albino pied, you can get:

2:4 Albinos 50% chance het Pied
2:4 Het Albinos 50% chance het Pied

For double het x double het, you can get:

9:16 66% chance het Albino, 66% chance het Pied (33% chance double het)
3:16 Albino 66% chance het Pied
3:16 Pied 66% chance het Albino
1:16 Albino Pied

As per OP's original question, I would suggest a pinstripe male to breed to the bumblebee female (or a pinstripe female to breed to the pastel if you would rather go for killerbees and lemon blasts than just going for spinner blasts, but that just boils down to personal preference). I wouldn't get a spider though, as you already have the bumblebee for that. If you go with the male pinstripe, I would also suggest breeding that to the normal female.

Quote:

---

Originally Posted by Russ Lawson

The way you have it written out looks pretty confusing, and is a bit redundant because you are writing out both phenotypes as well as genotypes. For albino x dh albino pied, you can get:

2:4 Albinos 50% chance het Pied
2:4 Het Albinos 50% chance het Pied

For double het x double het, you can get:

9:16 66% chance het Albino, 66% chance het Pied (33% chance double het)
3:16 Albino 66% chance het Pied
3:16 Pied 66% chance het Albino
1:16 Albino Pied

As per OP's original question, I would suggest a pinstripe male to breed to the bumblebee female (or a pinstripe female to breed to the pastel if you would rather go for killerbees and lemon blasts than just going for spinner blasts, but that just boils down to personal preference). I wouldn't get a spider though, as you already have the bumblebee for that. If you go with the male pinstripe, I would also suggest breeding that to the normal female.

---

Yeah, LOL, I wanted to make sure I didn't miss anything :rolleyes:.

Welcome to the forum :)

Quote:

---

Originally Posted by AdamM

Hey guys, new to the forum here but not new to snakes. Tomorrow I'm heading to the SC show and looking to pick up another BP. Nothing too freaky, I was thinking about a Spider or a Pinstripe, add some dominant traits into my mix. Currently I have 0.1 Piebald, 0.1 Bumblebee, 0.1 Normal, 1.0 Albino and a 1.0 Pastel. Would either of the 2 I mentioned, in your opinion be a good match for my collection combo for breeding? And would you suggest a male or a female?

Also I'm still unclear as to how the recessive trait works, if I breed my male albino to my female piebald, will it yield all hets or will I get any visuals ie: albino piebalds?

Sorry for all the questions in one post but as you can tell by my sig I mostly deal in arboreal snakes and what you see is pretty much what you get with the parents.

---

Welcome to the forum. Both snakes mentioned in red are codominant, not dominant. Also...I would go with the pin. You can produce your own spiders with the bumblebee.

Hi,

Quote:

---

Originally Posted by demjor19

Welcome to the forum. Both snakes mentioned in red are codominant, not dominant. Also...I would go with the pin. You can produce your own spiders with the bumblebee.

---

Not officially so far as I know - there are rumours of a homozygous spider and homozygous pinstripe - but neither is said to be visually different from the heterozygous form so they are still considered dominant.

Unless you have read something we haven't seen yet in which case please share? :please:


dr del

http://ballpython.ca/genetics.html

The text below can be applied to any simple recessive gene:
piebald, albino, axanthic, genetic stripe, hypo(ghost), lavender albino, caramel albino, etc.

this page may help you a lot. Pieds, or piebald is a simple recessive mutation. This means, that both parent animals need to have at least one copy of the gene in question to have the possibility of producing offspring that not only carry the gene, but display the trait that it carries.

Hets, or heterozygous animals, are animals that CARRY the gene but do not display it. They look completely normal. You can not tell which animals in a clutch are hets unless you bred a visual animal (in this case a pied) to a female. ALL the offspring produced would have one copy of the gene (in this scenario it came from dad) so they would be 100% het/heterozygous pied.

100% hets - animals known to be carrying the questioned gene.

66% hets - these animals are produced by breeding two 100% hets together. Once they are proved out by breeding, they either ARE heterozygous or NOT heterozygous for the gene in question. This does not mean that 66% of the babies will be pied/carry the pied gene/etc.

50% or possible hets - these animals are produced by breeding a 100% het animal to a normal animal. The babies have a 50% chance of carrying the gene in question. Like the 66% hets, these guys need to be proven to be het or not by breeding

Quote:

---

Originally Posted by dr del

Hi,



Not officially so far as I know - there are rumours of a homozygous spider and homozygous pinstripe - but neither is said to be visually different from the heterozygous form so they are still considered dominant.

Unless you have read something we haven't seen yet in which case please share? :please:


dr del

---

I know a few years back, a lot of people incorrectly were calling any mutation with a visually distinct heterozygous phenotype codominant (even if there had not been a homozygous form hatched yet). That poster may have heard them called codominant in the past. Lately though, it's shifted to more of a "dominant until proven otherwise" mentality, which is probably a better way to go about it...