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Genetics question

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  • 08-10-2013, 04:37 AM
    SnakeGriffin
    Genetics question
    Sorry if there was a thread posted on this already but I couldn't see one related to this question in particular. If I were to breed let's say a Clown Male or Female to a Lesser Male or Female. What would the resulting babies be? Would all the Lessers in that clutch be het for clown? I tried using a punett square but I couldn't figure it out entirely. Makes me wish I payed attention to all that stuff in High School about mating trees and what not. :(
  • 08-10-2013, 04:52 AM
    galequin
    Far as I know half would be lessers half would be normal het for clown I'm sure someone will direct you yo worldofballpythons.com's genetic wizard but this is much simpler ;) if you haven't used it yet give it a whirl I spend hours just playing with that thing planning hypothetical breeding scenarios
  • 08-10-2013, 05:07 AM
    galequin
    Whole clutch would be het for clown though sorry if that was unclear
  • 08-10-2013, 07:24 AM
    Pythonfriend
    one way to calculate it in your head is to look at the genes individually, one by one.


    - clown bred to normal produces what? that will be a uniform clutch of 100% het clowns.
    - and lesser bred to normal? half will be lessers, the other half will be normals.
    put both together. one half will be lesser het clown, the other half will be het clown.

    a more complicated example: super pastel to queen bee (lesser pastel spider).

    - Super pastel to pastel. Because of the super, all will at least have pastel in them. add another pastel, and half will be pastel, the other half super pastel.
    - add spider. one copy present, so half will get spider, the other half wont.
    - same with lesser: one half gets it, the other doesnt.

    now put it together: 50% pastel and 50% super pastel, and half get the spider gene. that results in 25% pastel, 25% super pastel, 25% pastel spider, 25% super pastel spider. Half of that get the lesser gene, so you get: 12,5% pastel, 12,5% super pastel, 12,5% pastel spider, 12,5% super pastel spider, 12,5% pastel lesser, 12,5% super pastel lesser, 12,5% pastel spider lesser, 12,5% super pastel spider lesser. Basically to add a gene that half the offspring will get, you split all the results you currently have into two halves, and one of these halves gets the gene.

    an example with one more complication: Pewter (cinnamon pastel) to pastel.

    - pastel to pastel gives you 25% normals, 50% pastel, and 25% super pastel.
    - half of them get cinnamon
    both combined: 12,5% normals, 25% pastel, 12,5% super pastel, 12,5% cinnamon, 25% pastel cinnamon, 12,5% super pastel cinnamon.


    punnet squares work, but have their own complications. You need to work out all possible contributions of the male, and put them on one axis. then you need to work out all possible contributions of the female, put it on the other axis. Then you draw the square, fill all the boxes, and then you need to pull the data out of the square. Often its not even a square, depending on pairings you could get an 8x4 box with 32 little boxes inside.
  • 08-10-2013, 12:12 PM
    paulh
    Re: Genetics question
    Pythonfriend is using a branching system instead of a Punnett square. Different method, same results.

    For a comparison of Punnett square and branching system, see post 67 in http://www.reptileforums.co.uk/forum...enetics-7.html
  • 08-10-2013, 12:40 PM
    OhhWatALoser
    say Lesser = Llcc and Clown = llCC, list all possible scenarios for each parent, which would be Lc and lc for the lesser and lC for the clown.

    Lc lc
    lC LlCc (Lesser het Clown) llCc (Het Clown)
  • 08-10-2013, 03:01 PM
    Pythonfriend
    Re: Genetics question
    Quote:

    Originally Posted by OhhWatALoser View Post
    say Lesser = Llcc and Clown = llCC, list all possible scenarios for each parent, which would be Lc and lc for the lesser and lC for the clown.

    Lc lc
    lC LlCc (Lesser het Clown) llCc (Het Clown)

    Now you make me want to try it out with a more complicated example :) lets say pewter to lesser pastel...

    Pewter: PpCcll, possible offspring: PCl, pcl, pCl, Pcl. Lesser pastel: PpccLl, possible offspring: PcL, pcl, Pcl, pcL

    PCl pcl pCl Pcl
    PcL PPCcLl (lesser sterling) 6,25% PpccLl (lesser pastel) 12,5% PpCcLl (lesser pewter) 12,5% PPccLl (super pastel lesser)6,25%
    pcl PpCcll (pewter) 12,5% ppccll (normal) 6,25% ppCcll (cinnamon) 6,25% Ppccll (pastel) 12,5%
    Pcl PPCcll (sterling) 6,25% Ppccll (pastel) second hit PpCcll (pewter) second hit PPccll (super pastel) 6,25%
    pcL PpCcLl (lesser pewter)second hit ppccLl (lesser) 6,25% ppCcLl (lesser cinnamon) 6,25% PpccLl (lesser pastel) second hit

    umm, yeah, it works....But i should have arranged it differently, so that the normal is in the lower right corner. I guess the "branching method" works better for me, i didnt even know it had a name :). Instead of making a box, you just manipulate one string of information, and you dont need to add the morphs together that you can get in different ways in the square.
  • 08-11-2013, 02:04 AM
    galequin
    Holy crap! My head is spinning! Ever understand something w/out knowing exactly why? Some real brains here on this forum bravo guys!
  • 08-12-2013, 11:55 AM
    paulh
    Re: Genetics question
    Quote:

    Originally Posted by Pythonfriend View Post
    Now you make me want to try it out with a more complicated example :) lets say pewter to lesser pastel...

    Pewter: PpCcll, possible offspring: PCl, pcl, pCl, Pcl. Lesser pastel: PpccLl, possible offspring: PcL, pcl, Pcl, pcL

    Branching system:
    Pp x Pp --> 1/4 PP, 2/4 Pp, 1/4 pp
    Cc x cc --> 1/2 Cc, 1/2 cc
    ll x Ll --> 1/2 Ll, 1/2 ll

    ________________1/2 Ll = 1/16 PP Cc Ll
    ________1/2 Cc <
    ________________1/2 ll = 1/16 PP Cc ll
    1/4 PP <
    ________________1/2 Ll = 1/16 PP cc Ll
    ________1/2 cc <
    ________________1/2 ll = 1/16 PP cc ll

    ________________1/2 Ll = 2/16 Pp Cc Ll
    ________1/2 Cc <
    ________________1/2 ll = 2/16 Pp Cc ll
    2/4 Pp <
    ________________1/2 Ll = 2/16 Pp cc Ll
    ________1/2 cc <
    ________________1/2 ll = 2/16 Pp cc ll

    ________________1/2 Ll = 1/16 pp Cc Ll
    ________1/2 Cc <
    ________________1/2 ll = 1/16 pp Cc ll
    1/4 pp <
    ________________1/2 Ll = 1/16 pp cc Ll
    ________1/2 cc <
    ________________1/2 ll = 1/16 pp cc ll

    Multiply fractions while going out each branch.
    1/16 = 6.25%
    2/16 = 12.5%
    This is easier to do with pencil and paper than with a text editor.
  • 08-12-2013, 11:59 AM
    Tribal
    :rolleye2:
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