Give Me an Example #1

On the super pastel woma spider pinstripe project you are severely handicapped in that there may not be a homozygous spider or even pinstripe and it doesn't sound like the homozygous woma could breed.

So your best pair would probably be super pastels so that you get 100% homozygous on the pastel side but one copy each of the spider, pinstripe, and woma gene would be spread through the parents (i.e. maybe super pastel spider pinstripe X super pastel woma - maybe there are names for those, but the pairing of pinstripe, spider, and woma on the two sides shouldn't matter unless some of these turn out to be linked). This would only yield 1 in 8 super pastel woma spider pinstripes and unless there are breedable homozygous versions of woma, spider, or pinstripe that is the best you could do, never up to 100%.

As far as the others:

"Het Spider X Het Pastel : 25% chance of Bumble Bee's, 25% chance of Spiders, 25% chance of Normals, and 25% chance of Pastels."

Right, see how realizing that spiders and pastels are hets helps figure out the offspring.

"Het Pastel X Bumble Bee: 12.5% chance of Killer Bee, 25% chance of Pastel, 12.5% chance of Pastel, 12.5% chance of Bumble Bee, 25% chance of Spider, 12.5% chance of Super Pastel, and 12.5% chance of Normal."

I think this one would be 12.5% chance killer bee, 12.5% chance super pastel, 25% chance bumble bee, 25% chance pastel, 12.5% chance spider, 12.5% chance normal. Basically you take the 25/50/25 chances of homozygous, heterozygous, and normal for pastel just like with any het X het breeding and split them in half for the spider overlay.

"Het Pastel X Homo Spider: 50% chance of Bumble Bee, 50% chance of Spider."

This requires that there is a breedable homozygous spider which is not publicly known but the theory is right if it exists.

"Het Spider X Super Pastel: 50% chance of Bumble, 50% chance of Pastel"

Right, again realizing that this is a het X homo breeding.

"Bumble Bee X Super Pastel: 25% chance of Killer, 25% chance of Super Pastel, 25% chance of Bumble Bee, and 25% chance of Pastel."

Right, you take the homo X het results from the pastel side of 50% homozygous (super) and 50% heterozygous (regular pastel) and then overlay the spider side's het X normal results of 50% spider and 50% normal for spider.

"Killer Bee X Super Pastel: 50% chance of Killer, 50% chance of Super Pastel."

Right again. Pastel side it's homozygous X homozygous so it's only the het spider X normal for spider part that makes any variety in this clutch.

I think I wrote down the Het Pastel X Bumble Bee down wrong but I think mine came out to be that. I'll double check. thanks for looking those over. I'm glad I got the majority right.

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Originally Posted by Jay_Bunny

But the albino doesn't carry the normal allele does it. It is recessive so in order for it to display the albino coloration, it would be homozygous recessive. The spider, if het, would carry only one allele for normal, right? Therefore you couldn't have normals. I'm probably all messed up on this, right?

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Oooh boy, this is my introductory post and here I am jumping in on whether or not you can have "het" dominant or co/incomplete dominant genes.

A standard-patterned Albino does not carry a normal "not-albino" gene.
However, what it DOES carry is two normal "Not-Spider" genes.
Therefore... it's perfectly possible for an Albino X Spider breeding to produce normals het for albino - if your spider is a heterozygous one.

I think part of the problem is that people mix up "recessive" with "heterozygous" and "dominant" with "homozygous".

So here's my quiz question:

What could you possibly get if you cross an Albino Spider with a Jigsaw (Pinstripe Mojave) - and how would the results be different if one or the other animal was homozygous for their dominant trait instead of heterozygous?

my guess...

youd get pinstripes mojaves spiders and jigsaws all het for albino.

All the babies would be het for albino and each egg would also have an independent 50% chance of being (visible) het for spider, pinstripe, and/or mojave. The combined chance of hitting all three would be 1 in 8.

The only one of those three (spider, pinstripe, and mojave) with a proven homozygous would be mojave so if one of the parents was homozygous mojave then it would be just like the homozygous albino, all the babies would be het mojave (and het albino) and only the spider and pinstripe would mutations have the 50% chance odds each.

Seems like simple bio talk, i am takin that class right now. just set up a chart with the traits and fill in the middle. whats co dom again?

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Originally Posted by k1ingdomKaa

Seems like simple bio talk, i am takin that class right now. just set up a chart with the traits and fill in the middle. whats co dom again?

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Co-dom is an expression of the genotype when it is heterozygous. But not completely dominant.

Pastel x Normal=you can get pastels and normals.

NN:normal
P*N:pastel
P*P*:super pastel

LOL, did that make sense to anyone? haha

The homozygous form of a co-dom can create the super form.

It gets even more complicated and fun than that, JoshJP7....

Because Pinstripe and Spider combine to make Spinner and you can ALSO get Spider Mojaves....

I'd expect that you'd get the following from an Albino heterozygous Spider X Mojave heterozygous Pinstripe:

Normal het Albino
Spider het albino
Pinstripe het albino
Mojave het albino
Spinner het albino
Jigsaw het albino
Spider Mojave het albino
Spider Jigsaw het albino