50% het?

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Originally Posted by Dave Green

66%

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hmmm.... how did you calculate that? I dont understand.

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Originally Posted by CH2O2

hmmm.... how did you calculate that? I dont understand.

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If you breed het x het each normal looking hatchling will have a 66% of being a het and a 33% chance of being a normal. It doesn't matter if there is one normal looking hatchling or four normal looking hatchlings each one has a 66% chance of carrying the recessive gene.

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Originally Posted by Dave Green

If you breed het x het each normal looking hatchling will have a 66% of being a het and a 33% chance of being a normal. It doesn't matter if there is one normal looking hatchling or four normal looking hatchlings each one has a 66% chance of carrying the recessive gene.

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I don't understand how that can be. Can you show me the mathematical calculation you make to arrive at the number 66%? I understand that would be the case if you have 3 normal looking snakes and 2 of them are het. 2 out of 3 is 66%. But how do you arrive at 66% when you have a clutch of 4 normal looking snakes from a het x het?

It doesn't matter how many eggs are in the clutch the % is per egg. It could be just one egg, that egg has a 66% chance of being het, it could be 2 eggs and each egg's individual chance of being het is 66% in that case. Someone needs to find the math, I'm sure its been posted before somewhere.

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Originally Posted by CH2O2

I don't understand how that can be. Can you show me the mathematical calculation you make to arrive at the number 66%? I understand that would be the case if you have 3 normal looking snakes and 2 of them are het. 2 out of 3 is 66%. But how do you arrive at 66% when you have a clutch of 4 normal looking snakes from a het x het?

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It doesn't matter how many you have, each one has a 66% chance of carrying the recessive gene...

Ok I will give it a whirl.

Het Albino x Het Albino (5 Eggs) offspring result in 1 Albino and 4 66% Possible Het Albinos

The odds are per egg so there are 3 possibilities per egg: Albino, Het Albino, Normal

We know the normal offspring are not albino but they can be het albino or normal. So out of the 3 possibilities in this breeding they can only be 2 out of the 3.

2/3=.666667*100=66.67% or 66% Possible Het Albino

So out the the 4 normal looking offspring each has a 66% chance of being Het Albino.

The same would work for a Het Albino x Normal pairing showing the 50% possible Het Albino.

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Originally Posted by CH2O2

I don't understand how that can be. Can you show me the mathematical calculation you make to arrive at the number 66%? I understand that would be the case if you have 3 normal looking snakes and 2 of them are het. 2 out of 3 is 66%. But how do you arrive at 66% when you have a clutch of 4 normal looking snakes from a het x het?

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parent one has one recessive allele and one normal allele
parent two has one recessive allele and one normal allele
egg #1 has 4 possibilities
1. to receive both recessive alleles
2. to receive recessive allele from parent one and normal allele from parent two
3. to receive normal allele from parent one and recessive allele from parent two
4. both normal alleles

If the egg gets both recessive alleles it is easily identified.
If the egg gets only 1 recessive allele or both normal alleles, they cannot be distinguished form each other.
you have 3 options
1. to receive recessive allele from parent one and normal allele from parent two
2. to receive normal allele from parent one and recessive allele from parent two
3. both normal alleles

so the chance of the egg getting a recessive allele is 2/3 or 66%
repeat the above for each other egg in the clutch.

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Originally Posted by OhhWatALoser

parent one has one recessive allele and one normal allele
parent two has one recessive allele and one normal allele
egg #1 has 4 possibilities
1. to receive both recessive alleles
2. to receive recessive allele from parent one and normal allele from parent two
3. to receive normal allele from parent one and recessive allele from parent two
4. both normal alleles

If the egg gets both recessive alleles it is easily identified.
If the egg gets only 1 recessive allele or both normal alleles, they cannot be distinguished form each other.
you have 3 options
1. to receive recessive allele from parent one and normal allele from parent two
2. to receive normal allele from parent one and recessive allele from parent two
3. both normal alleles

so the chance of the egg getting a recessive allele is 2/3 or 66%
repeat the above for each other egg in the clutch.

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Thanks seems your way is much more accurate than mine. :gj:

I will stay out of these conversations. LOL

You can also draw out the Punnett square to get a visual of what is going on.

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Originally Posted by CH2O2

How can you distinguish het pieds from normals?

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There are subtle clues. For instance, most have markers on the rear third of the belly in the form of thick black lines along the sides. I can only speak for my line of pieds. Not only do mine have the "tracks", they also have yellow-orange smudges on the belly.

When combining pied with other co-dom morphs, sometimes the pied gene will alter the look of the co-Dom gene. I have seen this in pewters, cinnies, sterlings, and possibly super pewters and silver bullets. I have some animals that I should prove out this season....and maybe even hatch more unseen stuff.