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  • 03-22-2006, 12:55 AM
    RandyRemington
    Re: double recess. x double recess. but diff. morph
    Using caramel hypos ("caramel glow" I think) X hypo pieds:

    cchhPP = caramel hypo (normal for pied)
    CChhpp = hypo pied (normal for caramel)

    Since both parents are homozygous hypo neither has a normal copy of that gene to give so all the babies will be homozygous hypo. However, they will also be hets for both caramel and pied --> CchhPp

    Now if you had 4 different genes in the two double homozygous recessive parents, like say snow X striped ghost you would end up with quadruple het babies:

    aazzSSHH X AAZZsshh = aAzZsShH

    Crossing two of those quadruple hets would in theory (if there is no linking of any of the 4 mutations) give you 1 in 256 stripped snow glow. But the upside is it would also only give you 1 in 256 completely normal that wasn't het for any of the four. The clutch variety from such a pair would be staggering.
  • 04-07-2006, 07:57 PM
    Mendel's Balls
    Re: double recess. x double recess. but diff. morph
    Quote:

    Originally Posted by RandyRemington
    Using caramel hypos ("caramel glow" I think) X hypo pieds:

    cchhPP = caramel hypo (normal for pied)
    CChhpp = hypo pied (normal for caramel)

    Since both parents are homozygous hypo neither has a normal copy of that gene to give so all the babies will be homozygous hypo. However, they will also be hets for both caramel and pied --> CchhPp

    Now if you had 4 different genes in the two double homozygous recessive parents, like say snow X striped ghost you would end up with quadruple het babies:

    aazzSSHH X AAZZsshh = aAzZsShH

    Crossing two of those quadruple hets would in theory (if there is no linking of any of the 4 mutations) give you 1 in 256 stripped snow glow. But the upside is it would also only give you 1 in 256 completely normal that wasn't het for any of the four. The clutch variety from such a pair would be staggering.

    Great post....

    For any pair of recessive traits.....the probabilty of obtaining a recessive from the breeding of two het parents is (1/(4^n) , where n is the number of recessives in question . by ^ I mean exponent!

    So for 1 recessive trait it would be 1/4^1 or 1/4 (25% chance). for two it would be 1/(4^2) or 1/16 (6.25% chance).

    1/256 chance is really small but it would be awesome to obtain a quad reccessive.
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