Question about getting Albinos.

Actually i don't think i'm wrong because if your snake lats four eggs and all four hatch then out of those four egg you would have a 25% chance to get an albino. if you go to the Genetics Wizard it will show you that breeding two 100% will give you three that look normal but out of those three two are 66% chance to be hets. while one should be albino but with breeding hets you have no promise of an albino. in fact here is a very good way to look at breeding stright from the nerd site "Something to keep in mind when dealing with punnett squares and simple recessive genetics is that the numbers involved are theoretical. For example, according to theory, breeding a 100% het-albino (Na) ball to an albino (aa) ball should yield half hets and half albinos out of 4 eggs. It doesn't always work this way though...we've bred hets to homozygous animals and gotten all homozygous, we've also bred hets to homozygous animals and gotten all hets. Depending on how the alleles fall, it's possible to breed two hets together and get all possible hets, or do the same and get all homozygous animals as a result. This can be very exciting or somewhat disappointing, depending on what you were expecting out of the clutch. That's a big reason why it's important to keep these numbers in mind as a hypothetical, best-case-scenario according to the laws of genetics. At the same time, that's what makes working with color morphs both extremely fun and also nerve-wracking!"

Basically, (0.75)^4 is the odds of all 4 offspring turning out to be normals or hets, since there is a 75% chance of each one being a normal or het and there are 4 of them.

So, if you subtract it from 1 you get the odds of not all 4 offspring turning out to be normals or hets. In other words, the odds of at least one turning out to be albino.

Quote:

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Originally Posted by gncz73

Actually i don't think i'm wrong because if your snake lats four eggs and all four hatch then out of those four egg you would have a 25% chance to get an albino.

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25% is the odds of 1 turning out to be albino. That is for each and every offspring independent of what the others turn out to be. As I said before, if you hatch out one, you have a 25% chance of getting an albino. For each additional offspring the odds change.

Clutch of 1: 25%
Clutch of 2: 1 - (0.75)^2 = 44%
Clutch of 3: 1 - (0.75)^3 = 58%
Clutch of 4: 1 - (0.75)^4 = 68%

Probabilities change when you have multiple trials. The genetics pages are just to tell you the odds of what any single given offspring turns out to be. It doesn't tell you the odds of getting an albino in a clutch, as they would have to give you percentages for every single clutch size. If you don't believe, go read up on probability and statistics: I was almost a math minor and I took 3 courses on probability & statistics so I'm pretty certain I know what I'm talking about :P

Awesome post hhw!

-adam

what would i get if i bred my normal male with an albino female?

a het?

TokenLs: all the offspring would be 100% het for albino

HHW is correct in his genetic mathmatics.

The only breeding combo's that will equal a CHANCE to produce an albino are:

albino X albino
Het Alb X Het Alb
alb X Het Alb

The Hets may take time to prove out. You may not actually hit an Albino on your first breeding attempt. There are quite a number of variables that must be considered when trying to produce a non-dominate morph. The genetic mathmatics is just one aspect.

Here are some tables I made up with the chance of producing at least one recessive morph with various clutch sizes for various crosses. It's using the same formula HHW showed.

http://snakemorphs.home.comcast.net/odds.htm#table

we shall wait for some1 more experience w/bp breeding suchas KLG to help all of us solve the issues!