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  • 10-16-2013, 03:53 PM
    sorraia
    Quickest way (ETA: quickest way without actually having visual hets to work with) with best odds would be to get two visuals, breed together, then breed the double het offspring together. Next quickest would be to work with double hets (but you'll have a smaller chance of getting your double recessive).

    I'm planning on hypo axanthic ("true ghost") in the future. I have a pair of axanthics and a pair of hypos to accomplish this. I'll be breeding the hypos to the axanthics, then breeding the offspring back together in hopes of hitting the double recessive. It'll take a few years to complete.
  • 10-19-2013, 04:04 PM
    Juicebøx
    Just so I'm understanding the third generation pairing to create my own double recessives (in my case Lightning Pied)...

    I would make my double hets with an Axanthic male to Pied female (I know that I "should" go the other way around, but I am doing it this way so that I can pair the pied female with other morphs in the future...) I would then take those 100% dh offspring and breed them together. That covers generations 1 & 2.

    With Generation 3, I am taking all of the females, and pairing them with generation 2's males (100% dh), and putting one of the gen 3 males to the gen 2 females... right? Obviously I would be using any visuals from gen 3 that I got, in order to attempt prove out their other recessive gene. If I'm looking at the "odds" correctly, I want as many females as possible from generation 2, as long as I get one male (ideally), and for generation 3, I could get ALL females and that wouldn't be a problem, right?

    Here is the "real question"... wouldn't it make the most sense to breed the non-visual offspring with one of the original parents in order to try and prove out 1/2 of it's genetics? Obviously you can only prove out one side or the other... but I would think that pairing a normal looking generation 3 snake to the 100% hets would be the LAST pairing that I made. Would I would want to take a visual looking generation 3 male, and pair him with my visual pied female to try and prove out his het pied status, or just leave him alone completely until I have exhausted all other pairing?

    Am I thinking about this correctly, or am I missing something in my logic? I know this is a 6 year minimum project (from Axanthic - Piebald to possibly producing my first Lightning Pied), but I'd like to avoid as many pitfalls as I can. I have read the Best Practices for Ball Python Breeders article, but it doesn't really address the "best way" to deal with dual het snakes.
  • 10-19-2013, 04:28 PM
    T&C Exotics
    Re: Double recessive projects?
    Ok if you are going to lightening pieds the best way to do it is to take a pied breed it to an axanthic. All of the offspring from THAT breeding will be double het for lightening pied. Then take those offspring raise them up and breed them together to get the 1 in 16 chance of getting the desired results. There is no need to "prove" out either of the hets because you produced them so you know that they have the genes. End of story.
  • 10-19-2013, 05:11 PM
    Pythonfriend
    a complete reply to Juicebox:

    unless you have access to shortcuts, everything starts with breeding double het to double het. In these breedings you get stuff like axathic 66% possible het pied, and pied 66% possible het axanthic, which may be useful. But its all a race to get the first double recessive visual male.

    Once you have a visual axanthic pied, EVERYTHING changes. You can breed him to pied to make pied 100% het axanthic. You can breed him to axanthic to make axanthic 100% het pieds.

    The odds change dramatically. In all examples mentioned below, all hets produced are 100% guaranteed hets.

    axanthic pied to double het axanthic pied: 25% axanthic pied, 25% pied het axanthic, 25% axanthic het pied, 25% double hets.

    axanthic het pied to pied het axanthic: the same, 25% axanthic pied, 25% pied het axanthic, 25% axanthic het pied, 25% double hets. (with a visual double recessive male and some axanthic females and pied females you can make tons of these and do many of these pairings 1 generation later).

    axanthic pied to axanthic het pied: 50% axanthic pied, 50% axanthic het pied

    axanthic pied to pied het axanthic: 50% axanthic pied, 50% pied het axanthic

    and, for completion, finally: axanthic pied to axanthic pied for clutches of 100% axanthic pied.

    So, when you have the visual double recessive, everything changes, forever. If you have, for example, a leftover axanthix 66% possible het pied, you prove that out by breeding to a visual axanthic pied. Offspring will be some axanthic pieds in the best case, worst case you "only" get a clutch of axanthic 100% het pieds. Same with leftover possible double hets: in the best case both prove out and you hit axanthic pieds, in the worst case you make 100% double hets, if only one aspect of a possible double het proves out you get more axanthic het pieds or more pied het axanthics.

    its hard to get the first double recessive breeder, and then everything changes and everything gets easy. So whatever you do, you should race towards the first visual double recessive, producing more is easy from there.

    so in the first generation you breed axanthic to pied to get 100% double hets.

    second generation will be double het to double het, to beat that 1 in 16 chance and hit the double recessive. you also get some axanthic 66% possible het pied and some pied 66% possible het axanthic.

    if you miss out on the hit, third generation would be: Continue double het to double het breeding. And also breed axanthic 66% possible het pied to pied 66% posible het axanthic, awesome if it proves out, and if it doesnt prove out you at least get more 100% double hets. These breedings can also produce axathic 100% het pieds, and pied 100% het axanthics.

    Shortcuts would be to buy 100% double hets, or to buy a pied 66% possible het axanthic or an axathic 66% possible het pied. Breed these to 100% double hets or to each other.

    Possible double hets are not very useful, pied possible het axanthics and axanthic possible het pieds are useful, visual pieds and axanthics are also useful, and pied 100% het axanthics and axanthic 100% het pieds are extremely useful. And the visual double recessive is the crown jewel, like the joker in poker, changes the game.
  • 10-19-2013, 05:41 PM
    Pythonfriend
    a little helpful tool is to adopt the following gene count:

    a codominant or dominant counts as 1. a 100% proven het also counts as 1.

    a super form counts as 2. a visual recessive also counts as 2.

    in combos, you just use these rules and add it together. so for me a jigsaw is a 2, a killerbee is a 3 (its just 2 genes but there is super pastel in it), a killer spinner is a 4.

    now lets rank the relevant stuff:

    a het pied is a 1, as is a het axanthic.

    a possible double het is somewhere between 0 and 2.

    a visual pied is a 2. an axathic is also a 2. a 100% double het is also a 2.

    pied possible het axanthic and axathic possible het pied rank somewhere between 2 and 3.

    pied het axanthic and axanthic het pied rank at 3.

    the visual double recessive is at 4.

    now when you breed a 4 to a 2, you either get all 3s (axanthic pied to axanthic for axanthic 100% het pieds), or you get 2s, 3s, and 4s (axanthic pied to double het axanthic pied). Anyway it helps to always count morphs like this, also focus on the stuff ranked 2 and above, for a double recessive project the stuff ranked below 2 wont get you far. Work up from 2 to 4.
  • 10-19-2013, 06:01 PM
    jimssnakes0808
    Re: Double recessive projects?
    I have my axanthic female in with my clown male as I write this looking for the 2nd lock.. im keeping all females back and 1 male and then putting him to all the females I get from the pairing.. good luck everyone this is what makes this great :D
  • 10-19-2013, 06:10 PM
    Emilio
    Re: Double recessive projects?
    I'm going Pied x Axanthic hopefully I'll produce at least 1.3 DH's to keep, then after I raise them up if all three breed I should hit on at least one lightning.


    Thats my plan.;)
  • 10-19-2013, 06:14 PM
    satomi325
    Re: Double recessive projects?
    Best would be breeding visual axanthic Het Pied and visual pied Het axanthic. However, that can be pricy. A pied and axanthic are relatively affordable these days. So you can go that route to produce double Hets.

    I have a double Het clown hypo project planned. I have a clown and pastel hypo that I'm going to pair next year. And I'm paying off a pastel lesser pH hypo clown that looks visually promising.

    Sent from my DROID RAZR using Tapatalk 2
  • 10-19-2013, 10:55 PM
    Juicebøx
    Re: Double recessive projects?
    Quote:

    Originally Posted by T&C Exotics View Post
    Ok if you are going to lightening pieds the best way to do it is to take a pied breed it to an axanthic. All of the offspring from THAT breeding will be double het for lightening pied. Then take those offspring raise them up and breed them together to get the 1 in 16 chance of getting the desired results. There is no need to "prove" out either of the hets because you produced them so you know that they have the genes. End of story.

    I know that all of generation 2 are 100% hets, especially because I will have produced them myself. I was talking about proving out the third generation... and Pythonfriend answered my question perfectly. I would take the Axanthic 66% het pied to Pied 66% Axanthic. Worst case scenario is I end up with another clutch of 100% DH.

    What would I do with the non-visual offspring from clutch 3? Do I breed them back with the original parents (generation 1) to attempt to prove out the 66%, or just breed them to each other, and see if I hit the odds? I am still trying to wrap my head around the "numbers stuff". It may take re-reading it a few times to understand it all.
  • 10-19-2013, 11:10 PM
    MootWorm
    Re: Double recessive projects?
    Breed the 3rd gen back to parents, who are known hets. If you breed PH sib to PH sib, you won't really prove anything out if one is a het and the other isn't... Make sense?
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