Breed axanthics

Hi people,

My axanthic female laying 4 eggs.
She was copulated with the male axanthic.

The axanthic morph is recessive, because I think that the babies can be:

25% (1 egg) Phenotype axanthic.
50% (2 eggs) Phenotype normal, het axanthic.
25% (1 egg) Pthenotype normal.

This is correct?

Axanthic X Axanthic = All Axanthic

Quote:

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Originally Posted by GA_Ball_Pythons

Axanthic X Axanthic = All Axanthic

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Not true with rescessive genes. the original poster was correct.

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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No. If you breed an Axanthic to Axanthic all babies will be Axanthic

Now if they were het Axanthic the thread starter would be right.

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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Sry wrong rescessive x rescessive = All rescessive

Quote:

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Originally Posted by Subzero

Not true with rescessive genes. the original poster was correct.

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Recessive x Recessive = ALL Recessives.

The original posters percentages were correct for a Het X Het breeding. All others are right with recessive X recessive 100% recessive.

Its not that recessive x recessive = all recessive, or that co-dom x co-dom does not.

For a particular trait -

Homozygous x Homozygous = all Homozygous

Homozygous x heterozygous =
50% Homozygous
50% Heterozygous

Heterozygous x Heterozygous =
25% Homozygous
50% Heterozygous
25% Normal

Heterozygous x Normal =
50% Heterozygous
50% Normal

REGARDLESS of whether the trait is recessive, co-dom or dominant.

So, if the OP's axanthics are homozygous, all babies will be homozygous (assuming the SAME LINE of axanthics). If they're hets, then his original assumptions are correct.

Steve

People,

Thank a lot.

Gabriel

Sorry...I forgot the last post: My BPs are 100% phenotype axanthic.