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Confusion
Alright...I'm just now starting to get seriously interested in breeding. I'm a little lost, however. Let's take Mojaves for example. When you breed a Mojave to a Normal you get a clutch that is 50% Mojave, 50% Normal, which means each baby has a 50/50 chance of being a Mojave or a Normal. Right so far?
Now are those Normals het for Mojave or just normal?
And, when you breed a Mojave and a Mojave, you get 25% Mojave, 25% Blue eyed Lucys, 25% Normal and 25%...what? Which means each baby has a 25% chance of being any one of those things, not that you will get 1/4 of each, right?
I guess what I'm really lost on is the whole het thing. Is each Normal from the breeding of two morphs het for that morph? How do you know if a snake is a het or a Normal?
Genetics was never my strong point. Please help! :confused:
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Re: Confusion
Quote:
Originally Posted by spix14
Alright...I'm just now starting to get seriously interested in breeding. I'm a little lost, however. Let's take Mojaves for example. When you breed a Mojave to a Normal you get a clutch that is 50% Mojave, 50% Normal, which means each baby has a 50/50 chance of being a Mojave or a Normal. Right so far?
Now are those Normals het for Mojave or just normal?
And, when you breed a Mojave and a Mojave, you get 25% Mojave, 25% Blue eyed Lucys, 25% Normal and 25%...what? Which means each baby has a 25% chance of being any one of those things, not that you will get 1/4 of each, right?
I guess what I'm really lost on is the whole het thing. Is each Normal from the breeding of two morphs het for that morph? How do you know if a snake is a het or a Normal?
Genetics was never my strong point. Please help! :confused:
There are no hets for mojave. The easiest way to remember is that co-doms only carry 1 gene in the pair for the visual trait. Mojaves themselves are basically visual hets for BELS. Since simple recesives need both genes to be there to get a visual, having only 1 gene makes it a normal looking het.
Mojo x mojo gets you 50% mojos, 25% BELs and 25% normals.
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Re: Confusion
Quote:
Originally Posted by spix14
How do you know if a snake is a het or a Normal?
Co-dominant genes are partially expressed when heterozygous, and have full expression when they are homozygous. (AKA, super)
Edit: man.. today is not my day for genetics... :(
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Re: Confusion
So the normals would just be normals right, since there's no het for mojave?
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Re: Confusion
Normal Mojave is HET. Blue eyed lucy is HOMOzygous. or the Super form of mojave. Heterozygous means that there is one copy of the gene, whereas homozygous (super) means it has 2 copies of the gene.
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Re: Confusion
Heres a very basic rundown of morph x normal breeding
Homozygous CoDom=Visual Morph (Super)
Het Codom=Visual Morph
Homozygous Recessive=Visual Morph
Het Recessive=Looks normal, carries gene
Dom=Shows morph No Homo form
Homo CoDom X Normal= 100% Het Codom (Visual morph)
Het CoDom X Normal= 50% visual 50% Normal
Homo Rec. X Normal= 100% Het (looks normal)
Het Rec. X Normal= 50% Carrying gene, all look normal
Dom X Normal= 50% visual 50% normal
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Re: Confusion
And if some day we have a proven dominant ball python morph you would need to know if the dominant animal was homozygous or heterozygous (since they look the same in dominant) to know if you are going to get 100% or only 50% chance per egg of the morph appearance.
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Re: Confusion
Now just a little question here! What about super dominates? While no visual difference would exist, it is something that would affect the punnett square and breeding of the ball python. Say you had a Super spider morph and bred it to a normal. All offspring would be spiders. No chance of a normal. Due to how the punnett square works this is possible, but would be very difficult if not impossible to prove in real life since the odds don't alway work the way they calculate out!
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Re: Confusion
Quote:
Originally Posted by Gloryhound
Now just a little question here! What about super dominates? While no visual difference would exist, it is something that would affect the punnett square and breeding of the ball python. Say you had a Super spider morph and bred it to a normal. All offspring would be spiders. No chance of a normal. Due to how the punnett square works this is possible, but would be very difficult if not impossible to prove in real life since the odds don't alway work the way they calculate out!
I don't think any Super Spiders have been produced... I think they have all died in the egg....
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Re: Confusion
There is simply no proof one way or the other if any homozygous spiders have been made.
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