Question about double recessive morph

What will happen if you breed the following
Albino Pied x Pied
Albino Pied x Albino
Albino Pied x Het Albino
Albino Pied x Het pied

...correct me if I'm wrong, what I'm guessing is

Albino Pied x Pied = All baby will be pied het Albino

Albino Pied x Albino = All baby will be Albino het pied

Albino Pied x Pied het Albino = half baby(in theory) will be Albino Pied, the rest will be Pied 66% het Albino

Albino Pied x Albino het pied == half baby(in theory) will be Albino Pied, the rest will be Albino 66% het Pied
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And to make this thread more confusing...
What's the chance of breeding Dom BP together?
For example

Spider x Pinstripe = ??? Again...my guesing is the following

Spider x Pinstripe = 25% chance of Spinner, 25% chance of Spider, 25% chance of Pinstripe, 25% chance of sib(which I'm sure if you get all this in one clutch then you'll call them sob lol)

My head hurts!

I believe you nailed the recessives. I'm not gonna comment on the dom, but I "think" that's correct as well.
Wolfy

Actually, when you breed Albino pied x Albino het pied you will get 1/2 Albino pied and 1/2 Albino 100% het pied. Albino pied x Pied het Albino you will get 1/2 Albino pied and 1/2 Pied 100% het Albino. If one of the parents is Double homozygous, all of the babies will be at least het.