100%, 66%, 50% het explaination help

I think I have this almost down but I am still a little confused.

I have a female piebald and a male spider 100% het pied. So my outcome is

1/4 (25%) Spied
1/4 (25%) Piebald
1/4 (25%) Spider het pied
1/4 (25%) Normal het pied.

The part I am confused about is the amount or percentage of het. My guess is they would both be 100%? Because two het parents would be 66% and a single het parent would give 50%? Is that right? I just want to make sure I have this right. I also have 2 het orange ghost/hypo BP so they would give me 66% hets?

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Originally Posted by BCS

My guess is they would both be 100%?

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Your guess is correct because of the visual pied parent. All of the offspring from your pied will get one copy of the pied gene from the female pied. Since your other spider is a het he only has one copy of the gene and will pass it on to 50% of his offspring. That's why you get (on average) half the offspring being visual pied. The other two are just hets (but they are 100% hets) because they are guaranteed a copy from the mother but missed out on a copy from the father.

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Originally Posted by Thomas Steele

Your guess is correct because of the visual pied parent. All of the offspring from your pied will get one copy of the pied gene from the female pied. Since your other spider is a het he only has one copy of the gene and will pass it on to 50% of his offspring. That's why you get (on average) half the offspring being visual pied. The other two are just hets (but they are 100% hets) because they are guaranteed a copy from the mother but missed out on a copy from the father.

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Okay one more. I have a sugar 100% het hypo and a Fire Woma 66% het hypo, would I still get the 66% hets? How would that work with one of the parents being 66% het?

Yes, if there is a visual animal that is a parent all animals will be at least 100% het.

If both parents are 100% het, offspring would be 66% het.
Example, 100% het pied x 100% het pied
1/4 Pied
1/4 normal het Pied
1/4 normal het Pied
1/4 normal

Of the non-visual animals, there is a 2/3 chance (or 66%) that each animal is carried the pied gene.


If one parent is 100% het, offspring would be 50% het.
Example, 100% het Albino x normal

1/2 normal het albino
1/2 normal

Of the non-visual animals, which in this case is the entire clutch, there is a 1/2 chance (or 50%) that each animal is carrying the Albino gene.

Hope that helps! I'm at work and couldn't find links with Punnett Squares at the moment.

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Originally Posted by BCS

How would that work with one of the parents being 66% het?

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So the 66% is just the odds of it being het. In reality it either is or it isn't. So the only real way to tell is if you produced a hypo from the pairing in which case you've then proven that the 66% het was actually a 100% het. Or you get no hypo and then you either got unlucky in the odds or it's not het hypo.

So you have two cases:
In the case of both parent's being het it's back to 66% het for the non-visual offspring.
In the case of Fire Woma not being het hypo it's 50% het (since one parent is 100% het) for the non-visuals.

I think it's easier when describing %'s for Hets to consider it as "How sure are you that it's a Het?"

66% means both its parents were 100% Hets, so your kinda sure.

50%, a little less sure, a coin toss.

1 of its parents were homozygous of the recessive gene? You are 100% sure.

Your 50% or 66% Het went on to lay/sire an offspring that was visual/homozygous for the recessive gene? Well, now your 100% sure it's a Het for that gene.

I never understood how this worked. It finally makes sense. Thank you!