Lesser X Spider Het Genetic Stripe
My question here is lets say one of the outcomes of this breeding would be a LesserBee het genetic stripe. With the het genetic stripe gene, will this LesserBee look different from a normal LesserBee ?
Will I be able to produce a Genetic Stripe ?
Re: Lesser X Spider Het Genetic Stripe
So with a Spider Het Genetic Stripe . How will I be able to breed it to produce Genetic Stripes and can just a Genetic Stripe or any other recessive be combined with other morphs to produce a new morph ? For example : Pastel X Spider = Bumblebee
Re: Lesser X Spider Het Genetic Stripe
Thank you very much Roach . I understand how it works now.
Just one last thing , in order to get a recessive morph to breed with a co or dominant morph and get the visual . 2 morphs which are bred together must have Het ?
Like in this case Lesser Het genetic stripe X Spider Het genetic stripe to get a chance of having a Lesser Genetic Stripe
Re: Lesser X Spider Het Genetic Stripe
Yes I have . Thank you very much for helping out :)
I'll continue searching the internet for more info on this
Re: Lesser X Spider Het Genetic Stripe
Genes come in pairs, but there are many gene pairs. The lesser mutant gene is in one pair, the spider mutant gene is is a totally different pair, the albino mutant gene is in a third gene pair, etc. And a baby gets one gene in each gene pair from each parent.
If we know the two genes in one of a baby's gene pairs, then figuring out the parents' gene pairs is just a logic problem. Say the baby is an albino. Albino is recessive to the corresponding normal gene, so the baby's gene pair has two albino mutant genes. One gene in each parent's gene pair must be an albino mutant gene. The male parent's other gene could be either a normal gene or an albino mutant gene. And the female's other gene could be either a normal gene or an albino mutant gene. That gives two possible male parents and two possible female parents.
male #1 = two albino genes = an albino
male #2 = one normal gene and one albino gene = a normal-looking het albino.
female #1 = two albino genes = an albino
female #2 = one normal gene and one albino gene = a normal-looking het albino.
To get any albino babies, the parents must be either two albinos, two normal-looking het albinos, or a het albino and an albino. Choice of parents depends on what is available in the market and how much money can be spent on the project.
The baby is a mojave. The mojave mutant gene is codominant to the corresponding normal gene. A mojave ball python has a mojave mutant gene paired with a normal gene. The father has either two mojave genes or two normal genes or a mojave gene paired with a normal gene. The mother has either two mojave genes or two normal genes or a mojave gene paired with a normal gene.
male #1 = two mojave genes = a super mojave ball python
male #2 = one normal gene and one mojave gene = a mojave ball python
male #3 = two normal genes = a normal ball python.
female #1 = two mojave genes = a super mojave ball python
female #2 = one normal gene and one mojave gene = a mojave ball python
female #3 = two normal genes = a normal ball python.
Male #1 can be mated to female 2 or 3 to produce mojave babies.
Male #2 can be mated to female 1 or 2 or 3 to produce mojave babies.
Male #3 can be mated to female 1 or 2 to produce mojave babies.
Male 1 cannot be mated to female 1 because all their babies would be super mojave rather than mojave.
Male 3 cannot be mated to female 3 because all their babies would be normals.
Choice of parents depends on what is available in the market and how much money can be spent on the project.
If there is more than one gene pair with mutant genes in the babies, you just go down the list one gene pair at a time.
Hope that helps.
