Het question

So this may sound dumb, but I am not 100% familiar with how hets work. Correct me if I'm wrong. If a person had a pied x pastel clutch, the babies wouldn't be 100% het for pied would they? Since only one parent was pied? Also, if two het pieds had a clutch, and some were normal, would they be het at all? Or just normal?

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If you have a visual piebald x pastel, all of the babies would be het piebald. The actual statistics are 1/2 pastel het piebald and 1/2 normal het piebald. Now if you did a het piebald x het piebald you would get 1/4 normal, 2/4 het piebald, and 1/4 piebald. So no, statistically they would not all be normals but they would also statistically not all be het piebald either. I hope that clears it up for you.

For the pied x pastel clutch, all of the offspring would be 100% het pied. This is because the pied in the pairing is passing along one copy of the pied gene to each offspring.

If both parents were pieds, all of the offspring would be pieds. This is because each parent would be passing along a copy of the pied gene. An animal has to have two copies of the pied gene in order for it to be visible. This is true with all recessive traits.

When you breed a pair of 100% het pieds together, the normal looking offspring have a 66% chance of inheriting a single copy of the pied gene. So the normal looking offspring are referred to as 66% het pied.

Hope this helps.

John

Visual Recessive x Visual Recessive = All Visual Recessive offspring
Visual Recessive x 100% Het = 1/2 Visual Recessive and 1/2 100% Het offspring
Visual Recessive x Normal = 100% Het offspring
100% Het x 100% Het = 66% Het offspring
100% Het x Normal = 50% Het offspring

Normal can be anything besides an animal that carries the recessive gene ie. Pastel, Spider, Mojave etc...

Edit: John beat me!

Here is a simple look at how the het to het works. This is how all hets work but I used piebald for the example I made here.

http://imageshack.us/a/img202/5007/hetv.png

This basically shows your odds of what you will get when pairing het x het. As you can see the NN is a complete normal with no het (1/4), the two Np are the normal het piebald (2/4), and finally the pp is the visual piebald (1/4). As specified by John, that means that all the normal looking babies would have to be labeled as 66% het piebald as you can not be 100% sure which are het piebald and which are not without holding them back and proving them out.

to go beyond what normal people even want to read, visual recessives are homozygous, just like a super pastel is homozygous. When you have a homozygous situation, the parent gives one gene or the other, since the two gene are exactly the same, the parent always passes one gene. So a pied to non-pied, you end up with all the babies being heterozygous (het). Same thing with a super pastel, it gives one pastel gene or the other, so all the babies end up with a pastel gene.

Male:	Piebald
Female:	Pastel
Percent	Fraction	Traits
50%	1/2	Pastel, Het Piebald
50%	1/2	Het Piebald
View Results Page

Male:	Het Piebald
Female:	Het Piebald
Percent	Fraction	Traits
25%	1/4	Piebald
75%	3/4	66% Possible Het Piebald
View Results Page

Ok, thanks guys. We are looking at getting some het pieds maybe next. I saw someone advertise some by a pied x pastel pairing, and said they were 100% het for pied. I was wondering where people get the 50% or 60% "het" from that I have seen.

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Quote:

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Originally Posted by DrDooLittle

I was wondering where people get the 50% or 60% "het" from that I have seen.

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66% is above, heres 50%

Male:	Het Piebald
Female:	Normal
Percent	Fraction	Traits
100%	1/1	50% Possible Het Piebald
View Results Page

Well you got your answer so I don't have much to add. The easy way to remember it, if one of the parents was a visual all the babies will be 100% hets. It gets really confusing when you start throwing in other recessives. And you get double hets from breeding two visual recessives, for example an albino to a pied. The babies would all look like normals, but would be 100% het pied and 100% het albino.