Butter x spider = 25% normal?

I ran this combo through the genetics wizard and it came out as follows : 25% butterbee, 25% butter, 25% spider, and 25% normal? I ran it multiple times with same results.

Is this right? Could i be missing something here? Why would i get normals ?

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Because neither parent is the super (homozygous) form of the gene. They can each contribute EITHER the morph gene or the wildtype/normal gene. If both parents contribute the normal gene, then you have a normal.

Both of those snakes are het not homo. so the punnett square would look like
s and b are normal phenotypes
B b (normal)

S BS Sb

s Bs bs

That is your normal

this could be wrong but this is how i see it.(that normal is not het for spider or butter)

As Annarose said both parents only have 1 codom gene (out of 2, if they had 2 they would be supers), so there is a 25% chance per egg that both parents will not pass the morph gene, resulting in a normal BP.

For more info on BP genetics I recommend checking out this helpful article by Judy: http://ball-pythons.net/forums/showt...Basic-Genetics

Quote:

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Originally Posted by Annarose15

Because neither parent is the super (homozygous) form of the gene. They can each contribute EITHER the morph gene or the wildtype/normal gene. If both parents contribute the normal gene, then you have a normal.

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x2 exactly
N n
N. NN. Nn

n. Nn. nn

If both snaks are codominant then you can either be lucky and get NN, a butterbee, or be unlucky and get nn, a normal. And Nn and Nn are spiders and butters.

Quote:

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Originally Posted by masonhall

Both of those snakes are het not homo. so the punnett square would look like
s and b are normal phenotypes
B b (normal)

S BS Sb

s Bs bs

That is your normal

this could be wrong but this is how i see it.(that normal is not het for spider or butter)

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I hate hatching bs out of eggs. :rofl:

co-doms carry wildtype genes.

Ok it makes sense. Its been a while since i crammed all this genetic stuff into my overwhelmed head. So many hobbies, so many things to keep track of. :) for some reason i was thinking visible morphs would pass only the morph gene. Thanks for the clarity guys!

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Also to add, there's always the possibility of producing all normals :D.
I don't wish that on anyone though.

Quote:

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Originally Posted by masonhall

Both of those snakes are het not homo. so the punnett square would look like
s and b are normal phenotypes
B b (normal)

S BS Sb

s Bs bs

That is your normal

this could be wrong but this is how i see it.(that normal is not het for spider or butter)

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Damn that heterozygous Spider gene. Grrrrrrr