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Thinking about breeding 100% Het Albino to 100% Het Albino @ 100% Het Pied to 100% Het Pied what would i get
100% het albino X 100% het albino= 25% Albino, 50% het Albino, 25% Normal 100% het Pied X 100% het Pied= 25% Pied, 50% het Pied, 25% Normal Of course these are just the chances you have at getting each
Also note, the probabilities depend on clutch size. The probabilities listed above are per egg. I.E. you have a 25% chance of getting a pied in any given egg when breeding het to het. In any given egg there is a 75% chance you will not get a pied. So take .75 and raise that value to the number of eggs you get. Ex 8 egg clutch: .75^8 = .100 = 10% chance of not getting a single pied in the entire clutch. Ex 4 egg clutch: .75^4 = .316 = 31.6% chance of not getting any pieds in the entire clutch.
Quote: Originally Posted by ChadOwens Also note, the probabilities depend on clutch size. The probabilities listed above are per egg. I.E. you have a 25% chance of getting a pied in any given egg when breeding het to het. In any given egg there is a 75% chance you will not get a pied. So take .75 and raise that value to the number of eggs you get. Ex 8 egg clutch: .75^8 = .100 = 10% chance of not getting a single pied in the entire clutch. Ex 4 egg clutch: .75^4 = .316 = 31.6% chance of not getting any pieds in the entire clutch. never thought to look at it that way...when you put it THAT way the outcomes don't seem so bleak!
Quote: Originally Posted by ChadOwens Also note, the probabilities depend on clutch size. The probabilities listed above are per egg. I.E. you have a 25% chance of getting a pied in any given egg when breeding het to het. In any given egg there is a 75% chance you will not get a pied. So take .75 and raise that value to the number of eggs you get. Ex 8 egg clutch: .75^8 = .100 = 10% chance of not getting a single pied in the entire clutch. Ex 4 egg clutch: .75^4 = .316 = 31.6% chance of not getting any pieds in the entire clutch. Also, you can take (1-the probability of getting zero pieds) to get the probability of getting at least 1 pied. I.E. in the 8 egg clutch example. (1-.75^8) = 90% chance of getting at least 1 pied in an 8 egg clutch.
