multi trait genetics question

Just curious, Does bumblebee x normal have the opportunity to produce bees? Can pastel kingpin x normal produce pastel kingpin? Im trying to see how the multi trait codom genetics pass along.
Thanks!

Yes to both, as long as there is no super form in there every co-dom/dom has the opportunity to transfer

A bumblebees DNA will have:

Spider-Normal
Pastel-Normal

So it has the chance of passing each gene to its offspring. Where as a super pastel has:

Pastel-Pastel

And can only pass on one pastel gene on because the other side is provided by the other parent.

Many mutations have a different locus (i.e. different genes) and are probably on different chromosomes or at least not close together on the same chromosome. In cases of combinations of unrelated mutations, the different mutations are inherited independently. The offspring from bumblebee X normal have separate 50/50 chances for each gene. It's like two different coin tosses. To find the combined chance of both mutations going to an egg you multiply the chances of each together. So in the case of two independent co-dom genes it's 0.5 X 0.5 = 0.25 or 25%. It's the same chance for getting a normal.

Things work a little differently when the two mutations are the same gene. Each parent only gives one copy of a gene so in the case of say a mystic potion which appears to be a combination of two mutations of the same gene (alleles, in this case mojave and mystic) the mystic potion can't give both versions of the same gene to the same offspring. Each offspring from mystic potion X normal would have a 50% chance of being mojave and a 50% chance of being mystic and no chance of being normal or mystic potion.

Some day we might find an example of two different mutations that are of different genes but those genes happen to be very close together. For example, if one of the axanthic mutations was close on the same chromosome as hypo it would be even more difficult than the unlinked case of 1 in 16 to produce a true ghost from breeding a pair of double hets together. It would require an odd number of crossovers to produce even the first copy of that chromosome with both mutations and then you would have to get two of those crossover copies together.