1.0 pied X 0.1 100% het pied????
how many pied's would that produce? what could i get
Re: 1.0 pied X 0.1 100% het pied????
Re: 1.0 pied X 0.1 100% het pied????
I'm a little confused - you just dropped $10K on all these animals and equipment, and you didn't research the details of your investment ahead of time? :confused:
It's also possible that you'll get all 100% het pieds (no pieds), or all pieds, it's all a roll of the dice.
Re: 1.0 pied X 0.1 100% het pied????
If you have a 100% het pied and a pied....
25% pied (possibly)
75% hets (possible 100% hets and no pieds)
You have to prove out the hets first....
Re: 1.0 pied X 0.1 100% het pied????
i knew somewhat of what i was doing but i've only been into the pythons a few months. i enough to know that it was a hell of a deal i was offered so i jumped on it. i got 45 adult/sub adult balls all the equitment amd a rat breeding colony. yes it was kinda on a whim and now im trying to put the pieces together.
Re: 1.0 pied X 0.1 100% het pied????
Quote:
Originally Posted by
sheffernan13
If you have a 100% het pied and a pied....
25% pied (possibly)
75% hets (possible 100% hets and no pieds)
You have to prove out the hets first....
lol, nope.
pieds or 100% hets, no proving anything :P
Re: 1.0 pied X 0.1 100% het pied????
50/50 could get more or less bad luck if you get 0.
Re: 1.0 pied X 0.1 100% het pied????
50% chance PER EGG of hitting on a Pied, however anything that isn't Pied is a 100% Heterozygous animal.
Re: 1.0 pied X 0.1 100% het pied????
You would get 50% of the clutch being het for Pied, 25% of the clutch being normal, and the other 25% of the clutch being Pied.
P= upper case dominant allele (PP= normal)
P= lower case recessive allele (pp= recessive)
Pp or pP= both upper and lower case alleles (Pp or pP= heterozygous)
100% het Pied x 100% het Pied
50%= heterozygous (alleles are Pp or pP)
25%= normal (alleles are PP)
25%= Piebald (alleles are pp)
Re: 1.0 pied X 0.1 100% het pied????
Quote:
Originally Posted by
CoolioTiffany
You would get 50% of the clutch being het for Pied, 25% of the clutch being normal, and the other 25% of the clutch being Pied.
P= upper case dominant allele (PP= normal)
P= lower case recessive allele (pp= recessive)
Pp or pP= both upper and lower case alleles (Pp or pP= heterozygous)
100% het Pied x 100% het Pied
50%= heterozygous (alleles are Pp or pP)
25%= normal (alleles are PP)
25%= Piebald (alleles are pp)
Sorry Tiff but not so, there wouldn't be any normals. Because there is a homozygous pied involved all babies would be at a minimum 100% het pied. As others have stated, this is a 50/50 situation.