"Pattimuss doesn't run, he prances most delicately, like a beautiful but sad fairy, winged and capped, curly toed shoes on each foot, dancing on dewdrops while lazy crickets play soft music for him to keep time by...." - Wes
Just remember that each parent has two copies of each gene but only passes one copy to each offspring. So even though both the super pastel's copies of the gene at the pastel locus are the pastel mutation it can only give one pastel mutant copy to each baby. The spider parent has two normal copies at the pastel locus so can only give one normal for pastel copy to each baby. So every baby is heterozygous for pastel (i.e. a Pastel) with one pastel copy from the super pastel parent and one normal for pastel copy from the spider parent.
The spider mutation is at a completely different locus so a separate problem. The super pastel has two normal for spider copies so each baby gets one normal for spider from the super pastel. The spider is heterozygous for the spider mutation with one normal for spider copy and one spider mutant copy so each baby has a 50/50 chance as to which type of the spider gene (mutant or normal) it gets from the spider parent.
So overlaying the two results (all pastel and 50% spider) you get the 50% chance just pastel and 50% chance both pastel and spider (bumblebee).
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Originally Posted by M&J in NC
