I'm trying to learn how to calculate double hets, I've done some searching on here, but math has never been a strong point for me. I understand how to combine say recesive genes on a punnet square. Say Albinos.

http://www.newenglandreptile.com/gen...recessive.html

a = albino gene
N = normal gene

aa = albino snake
aN = het albino
NN = normal bp

I can put that on a four box square and figure it out. I can even figure out a non recessive like a pastel, because I still consider the two genes.

p = Pastel gene
N = Normal gene

pN = Pastel
pp = Super Pastel
NN = Normal bp

I can even put that in a four square and figure it out. What I don't know how to do is mix Albinos and Pastels, with this method I can only work out hets, I don't know when it becomes a double het.

aa = Albino
pN = Pastel

aa x pN = ap, ap, aN, aN

ap = Pastel with 100% het for Albino
aN = 100% het for Albino

This is where I may need the help, someone please correct me if I'm wrong, I think I'm right up until here. http://www.newenglandreptile.com/gen...recessive.html (Section 1 is where I get confused. I don't know where they get the ccGG for Carmel Albino)

At this point I have what I believe is a double het. It is a Pastel looking snake with a het for Albino. (I'm going to consider Pastel as a het for Super Pastel) If this is true I have a snake that is het for Albino as well as Super Pastel.

My question is, how to I put my example and incorporate it to Section 1 of the link I gave.

I believe breeding these double hets, there is a chance of a pastel albino, but I'm not sure how to achieve it.