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Butter x spider = 25% normal?
I ran this combo through the genetics wizard and it came out as follows : 25% butterbee, 25% butter, 25% spider, and 25% normal? I ran it multiple times with same results.
Is this right? Could i be missing something here? Why would i get normals ?
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Re: Butter x spider = 25% normal?
Because neither parent is the super (homozygous) form of the gene. They can each contribute EITHER the morph gene or the wildtype/normal gene. If both parents contribute the normal gene, then you have a normal.
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The Following User Says Thank You to Annarose15 For This Useful Post:
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Registered User
Both of those snakes are het not homo. so the punnett square would look like
s and b are normal phenotypes
B b (normal)
S BS Sb
s Bs bs
That is your normal
this could be wrong but this is how i see it.(that normal is not het for spider or butter)
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As Annarose said both parents only have 1 codom gene (out of 2, if they had 2 they would be supers), so there is a 25% chance per egg that both parents will not pass the morph gene, resulting in a normal BP.
For more info on BP genetics I recommend checking out this helpful article by Judy: http://ball-pythons.net/forums/showt...Basic-Genetics
"We are artists using locus and alleles as our paint; the ball python as our canvas" - Colin Weaver

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The Following User Says Thank You to Adam Chandler For This Useful Post:
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 Originally Posted by Annarose15
Because neither parent is the super (homozygous) form of the gene. They can each contribute EITHER the morph gene or the wildtype/normal gene. If both parents contribute the normal gene, then you have a normal.
x2 exactly
N n
N. NN. Nn
n. Nn. nn
If both snaks are codominant then you can either be lucky and get NN, a butterbee, or be unlucky and get nn, a normal. And Nn and Nn are spiders and butters.
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 Originally Posted by masonhall
Both of those snakes are het not homo. so the punnett square would look like
s and b are normal phenotypes
B b (normal)
S BS Sb
s Bs bs
That is your normal
this could be wrong but this is how i see it.(that normal is not het for spider or butter)
I hate hatching bs out of eggs.
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The Following 4 Users Say Thank You to Mike41793 For This Useful Post:
decensored (05-03-2012),jben (05-05-2012),moonlightgdess (05-06-2012),snakesRkewl (05-03-2012)
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co-doms carry wildtype genes.
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Ok it makes sense. Its been a while since i crammed all this genetic stuff into my overwhelmed head. So many hobbies, so many things to keep track of. for some reason i was thinking visible morphs would pass only the morph gene. Thanks for the clarity guys!
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The Following User Says Thank You to Izzys Keeper For This Useful Post:
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Re: Butter x spider = 25% normal?
Also to add, there's always the possibility of producing all normals .
I don't wish that on anyone though.
0.1 Leopard Pied
0.1 VPI Axanthic Het Pied
1.0 VPI Axanthic Pied
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Re: Butter x spider = 25% normal?
 Originally Posted by masonhall
Both of those snakes are het not homo. so the punnett square would look like
s and b are normal phenotypes
B b (normal)
S BS Sb
s Bs bs
That is your normal
this could be wrong but this is how i see it.(that normal is not het for spider or butter)
Damn that heterozygous Spider gene. Grrrrrrr
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